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irina [24]
2 years ago
10

Product A is and 8oz bottle of cough medication that's sells for $1.36. Product B is 16oz bottle of cough medication that costs

$3.20. Which product has the lower unit price?
Mathematics
1 answer:
zhenek [66]2 years ago
4 0

Answer:

Product B

Step-by-step explanation:

Divide the number of ounces i the bottle by the price of the bottle. Product A has a unit price of $0.17 and Product B has a unit price of $0.20. Therefore Product B has a lower unit price :))

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A family needs to build fencing around their rectangular home and square swimming pool, depicted below. A rectangle labeled home
Andrej [43]

Answer:

The total amount of fencing they need can be written as  

38 x + 10.

If x = 5;

The family needs  160  yards of fencing for their home.

The family needs  40  yards of fencing for their pool.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
On a coordinate plane, a triangle has points (negative 5, 1), (2, 1), (2, negative 1).
daser333 [38]

Answer:

Step-by-step explanation:

Given a triangle has points:

(-5,1),(2,1), (2,-1)

Let us label the points:

A(2,1),

B(-5,1) and  

C(2,-1)

To find:

Distance between (−5, 1) and (2, −1) i.e. BC.

Horizontal leg AB and

Vertical leg, AC.

Solution:

Please refer to the attached diagram for the labeling of the points on xy coordinate plane.

We can simply use Distance formula here, to find the distance between two coordinates.

Distance formula :

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

For BC:

x_2 = 2\\x_1 = -5\\y_2 = -1\\y_1 = 1

BC = \sqrt{(2--5)^2+(-1-1)^2} = \sqrt{63}

Horizontal leg, AC:

x_2 = -5\\x_1 = 2\\y_2 = 1\\y_1 = 1

AC = \sqrt{(2-(-5))^2+(1-1)^2} = 7

Vertical Leg,  AB:

x_2 = 2\\x_1 = 2\\y_2 = -1\\y_1 = 1

AB = \sqrt{(2-2)^2+(-1-1)^2} = 2

5 0
2 years ago
Read 2 more answers
Carlos biked StartFraction 139 over 8 EndFraction miles on Saturday and StartFraction 135 over 7 EndFraction miles on Sunday. On
melomori [17]

Answer:

Carlos rode further than on Saturday by 107/56 miles.

Step-by-step explanation:

i did the quiz lol

7 0
1 year ago
Read 2 more answers
The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t
Aleksandr [31]
Width = x
Length = x+18

Assuming the table is rectangular:
Area = x(x + 18)

Therefore:
x(x + 18) <span>≤ 175
x^2 + 18x </span><span>≤ 175

Using completing the square method:
x^2 + 18x + 81 </span><span>≤ 175 + 81
(x + 9)^2 </span><span>≤ 256
|x + 9| </span><span>≤ sqrt(256)
|x + 9| </span><span>≤ +-16
-16 </span>≤ x + 9 <span>≤ 16
</span>-16 - 9 ≤ x <span>≤ 16 - 9
</span>-25 ≤ x <span>≤ 7
</span><span>
But x > 0 (there are no negative measurements):
</span><span>
Therefore, the interval 0 < x </span><span>≤ 7 represents the possible widths.</span><span>

</span>
3 0
1 year ago
Read 2 more answers
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation: 22, 18, 1
BigorU [14]

Answer:

a:  Sample mean: 20, Sample standard deviation: 1.732

b:  19.13 <µ < 20.87

c:  18.84< µ < 21.16

d:  as the confidence level increases, the interval becomes wider

Step-by-step explanation:

a:  Sample mean is found by adding up all the individual values of the sample, then dividing by the total number of values in the sample.  

Sample standard deviation is the square root of the variance

See the first attached photo for the calculations of these values.

We need to create a 80% confidence interval for the population.  Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.  

Look for the column on the t-distribution chart that has "area in two tails" of 0.20 (80%), and row 7 (degree of freedom)

The t-value is 1.415

See the second attached photo for the construction of the confidence interval

We need to create a 90% confidence interval for the population.  Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.  

Look for the column on the t-distribution chart that has "area in two tails" of 0.10 (90%), and row 7 (degree of freedom)

The t-value is 1.895

See the third attached photo for the construction of the confidence interval

3 0
2 years ago
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