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iragen [17]
1 year ago
5

A basketball team plays 3 games in a holiday tournament. According to the tree diagram, how many outcomes are possible?

Mathematics
2 answers:
kati45 [8]1 year ago
8 0

Answer:

Hence, the possible number of outcomes are:

Option: d ( d. 8)

Step-by-step explanation:

It is given that:

A basketball team plays 3 games in a holiday tournament.

(   We know that:

Tree diagrams display all the possible outcomes of an event. Each branch in a tree diagram represents a possible outcome )

The possible number of outcomes that are possible are:

8.

Let the team be denoted by 'A'

so, the outcome of the game may be winning(W) or losing(L) the game.

dybincka [34]1 year ago
6 0

Answer:

Option d. 8 is the correct option.

Step-by-step explanation:

A basketball team plays 3 games in a holiday tournament.

Let the chance of winning of the team be represented as W and losing by L

As per tree diagram attached we can see

In the first game

Number possibilities will be 2 either win or lose

After second games

Number of possibilities will be 4 [(L L), (L W), (W L), (W W)]

After third game

Number of possibilities will be 8 [ (L L), (L W), (W L), (W W), (L L), (L W), (W L),  (W W)]

So total outcomes which are possible are 8.

Option d. 8 is the correct option.

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LekaFEV [45]
The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.

For more context let's look at the first equation in the problem that we can apply this to: (x-3)(x+4)=0

Through zero property we know that the factor (x-3) can be equal to zero as well as (x+4). This is because, even if only one of them is zero, the product will immediately be zero.

The zero product property is best applied to factorable quadratic equations in this case.

Another factorable equation would be 2x^{2}+6x=0 since we can factor out 2x and end up with 2x(x+3)=0. Now we'll end up with two factors, 2x and (x+3), which we can apply the zero product property to.

The rest of the options are not factorable thus the zero product property won't apply to them.
3 0
2 years ago
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You just discovered that you have 100 feet of fencing and you have decided to make a rectangular garden. Assume the lengths of t
Tju [1.3M]

Answer:

10*10=100

50*2=100

5*20-100

Step-by-step explanation:


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2 years ago
Increase £16870 by 3% <br> Give your answer rounded to 2 DP
Naya [18.7K]

Answer:

17376.1 euros

Step-by-step explanation:

100%=16870

103%=x

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Zoe the goat is tied by a rope to one corner of a 15 by 25 meter rectangular barn in the middle of a large, grassy field. Over w
atroni [7]

Answer: 78.55\ m^2

Step-by-step explanation:

Given

The goat is tied by a rope to one corner of a rectangular field with length of rope 10 m.

Zoe can graze in an area equal to quadrant of circle with radius 10 m

Area of grazing is

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1 year ago
Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10
Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000  (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

5 0
1 year ago
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