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2 years ago

7

Manuel is also in Mr. Whittaker’s science class. He observed that the water level rose 1.8 millimeters per year, which matches t

he average annual trend. This occurred for 2.2 years. Explain how to determine the total variation in water level.

2 answers:

Savatey [412]2 years ago

8 0

Answer:

To determinethe total variation in water level you would multiply 1.8 by 2.2 (3.96) and I can check my answer by rounding 2.2 to 2 and 1.8 to 2 and multiply that which equals 4 and 4 is close to 3.96

Step-by-step explanation:

Degger [83]2 years ago

3 0

Answer:

yoi could determine by multiyplying

Step-by-step explanation:

because if you do you'll find the easy way out on dividing then multiplying

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Answer:

the answer is -0.018

Step-by-step explanation:

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1 year ago

Which is the domain of the function f(x) = Negative five-sixths (three-fifths) Superscript x?

amm1812

Answer:

All real numbers less than 0

Step-by-step explanation:

I think it's this one because greater than 0 is wrong

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1 year ago

Use green's theorem to compute the area inside the ellipse x252+y2172=1. use the fact that the area can be written as ∬ddxdy=12∫

Pavel [41]

The area of the ellipse $E$ is given by

$\displaystyle\iint_E\mathrm dA=\iint_E\mathrm dx\,\mathrm dy$

To use Green's theorem, which says

$\displaystyle\int_{\partial E}L\,\mathrm dx+M\,\mathrm dy=\iint_E\left(\frac{\partial M}{\partial x}-\frac{\partial L}{\partial y}\right)\,\mathrm dx\,\mathrm dy$

( $\partial E$ denotes the boundary of $E$ ), we want to find $M(x,y)$ and $L(x,y)$ such that

$\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1$

and then we would simply compute the line integral. As the hint suggests, we can pick

$\begin{cases}M(x,y)=\dfrac x2\\\\L(x,y)=-\dfrac y2\end{cases}\implies\begin{cases}\dfrac{\partial M}{\partial x}=\dfrac12\\\\\dfrac{\partial L}{\partial y}=-\dfrac12\end{cases}\implies\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1$

The line integral is then

$\displaystyle\frac12\int_{\partial E}-y\,\mathrm dx+x\,\mathrm dy$

We parameterize the boundary by

$\begin{cases}x(t)=5\cos t\\y(t)=17\sin t\end{cases}$

with $0\le t\le2\pi$ . Then the integral is

$\displaystyle\frac12\int_0^{2\pi}(-17\sin t(-5\sin t)+5\cos t(17\cos t))\,\mathrm dt$

$=\displaystyle\frac{85}2\int_0^{2\pi}\sin^2t+\cos^2t\,\mathrm dt=\frac{85}2\int_0^{2\pi}\mathrm dt=85\pi$

###

Notice that $x^{2/3}+y^{2/3}=4^{2/3}$ kind of resembles the equation for a circle with radius 4, $x^2+y^2=4^2$ . We can change coordinates to what you might call "pseudo-polar":

$\begin{cases}x(t)=4\cos^3t\\y(t)=4\sin^3t\end{cases}$

which gives

$x(t)^{2/3}+y(t)^{2/3}=(4\cos^3t)^{2/3}+(4\sin^3t)^{2/3}=4^{2/3}(\cos^2t+\sin^2t)=4^{2/3}$

as needed. Then with $0\le t\le2\pi$ , we compute the area via Green's theorem using the same setup as before:

$\displaystyle\iint_E\mathrm dx\,\mathrm dy=\frac12\int_0^{2\pi}(-4\sin^3t(12\cos^2t(-\sin t))+4\cos^3t(12\sin^2t\cos t))\,\mathrm dt$

$=\displaystyle24\int_0^{2\pi}(\sin^4t\cos^2t+\cos^4t\sin^2t)\,\mathrm dt$

$=\displaystyle24\int_0^{2\pi}\sin^2t\cos^2t\,\mathrm dt$

$=\displaystyle6\int_0^{2\pi}(1-\cos2t)(1+\cos2t)\,\mathrm dt$

$=\displaystyle6\int_0^{2\pi}(1-\cos^22t)\,\mathrm dt$

$=\displaystyle3\int_0^{2\pi}(1-\cos4t)\,\mathrm dt=6\pi$

3 0

2 years ago

A survey reported that 63.63% of moviegoers prefer action films.This percent represents a repeating decimal.write is as a fracti

Alenkasestr [34]

Let x = 63.63...(by repeating i assume you mean the 63 is repeated as 63.636363...)
therefore 100x = 6363.63..
100x-x =6300 (the recurring bit has been cancelled out which is what you should always aim to do)
99x=6300
x = 6300/99
cancel down
x = 700/11

7 0

2 years ago

At the time of her grandson's birth, a grandmother deposits $ 2000 in an account that pays 3.5 % compounded monthly. What will

11Alexandr11 [23.1K]

At the time of her grandson's birth, a grandmother deposits $12,000.00 in an account that pays 2% compound monthly. What will be that value of the account at the child's twenty-first birthday, assuming that no other deposits or withdrawls are made during the period.
---
A(t) = P(1+(r/n))^(nt)
---
A(21) = 12000(1+(0.02/12))^(12*21)
---
A(21) = 12000(1.5214)
---
A(21) = #18,257.15

7 0

2 years ago

Read 2 more answers