Complex solutions, namely roots with a √(-1) or "i" in it, never come all by their lonesome, because an EVEN root like the square root, can have two roots that will yield the same radicand.
a good example for that will be √(4), well, (2)(2) is 4, so 2 is a root, but (-2)(-2) is also 4, therefore -2 is also a root, so you'd always get a pair of valid roots from an even root, like 2 or 4 or 6 and so on.
therefore, complex solutions or roots are never by their lonesome, their sister the conjugate is always with them, so if there's a root a + bi, her sister a - bi is also coming along too.
if complex solutions come in pairs, well, clearly a cubic equation can't yield 3 only.
Answer:
a. 12
b. 7.200 and 2.683
Step-by-step explanation:
The computation is shown below:
Given that
P = 0.40 and n = 30
a)
The expected value of received e-mails is
= n × p
= 30 × 0.4
= 12
b)
The variance of emails received is
= n × p × (1 - p)
= 30 × 0.4 × 0.6
= 7.200
Now
The standard deviation of emails received is
= sqrt(variance)
= 2.683
We simply applied the above formula
Answer:
<u>The rabbit could be at eight different numbers of the number line:</u>
<u>-7, - 5, - 3, - 1, 1, 3, 5, and 7.</u>
Step-by-step explanation:
Let's simulate each of the jumps of the rabbit in all the possible directions, as follows:
Option 1: - 4 - 2 - 1 = -7
Option 2: - 4 - 2 + 1 = -5
Option 3: - 4 + 2 - 1 = - 3
Option 4: - 4 + 2 + 1 = - 1
Option 5: 4 - 2 - 1 = 1
Option 6: 4 - 2 + 1 = 3
Option 7: 4 + 2 - 1 = 5
Option 8: 4 + 2 + 1 = 7
D)$40 because you divide 2 and 48 then multiply 10 then you do 20 x 10 then subtract the two answers
The confidence interval would be (0.122, 0.278).
We first find our z-score. We want a 95% confidence interval:
0.95/2 = 0.475
Looking this up in the z-table, (http://www.statisticshowto.com/tables/z-table/) we see the z-score is 1.96.
The formula we will use is:

In this problem, p = 20/100 = 0.2, and n=100: