Where are the answer choices?
The answer is the first choice - see picture for solution:
The margin of error of a given statistic is an amount that is allowed for in case of miscalculation or change of circumstances.
It is usually the radius or half of the width of the confidence interval of that statistic.
Given that a<span>
survey of the students in Lance’s school found that 58% of the
respondents want the school year lengthened, while 42% think it should
remain the same. The margin of error of the survey is ±10%.
This means that 58% </span><span>± 10% of the </span>respondents want the school year lengthened, while 42% <span><span>± 10% think it should
remain the same.</span>
Thus, from 48% to 68% </span><span><span>of the respondents want the school year lengthened, while from 32% to 52% <span>think it should
remain the same.</span> </span>
Therefore, according to
the survey data, at least 32% of students want the duration of the school
year to remain unchanged, and at least 48% want the school year to be
lengthened.</span>
The right answer is:
<em>area B = area C</em>
We can solve this problem by using Kepler's laws of planetary motion. There are three Kepler's laws. In this exercise, we need to use the second law. According to this law,<em> a line segment joining a planet and the sun sweeps out equals areas during equals intervals of time. </em>So, a certain planet sweeps out an <em>area B </em>from the point <em>P3 </em>to <em>P4</em> in an interval of time <em>t. </em>On the other hand, for the same interval of time <em>t, </em>the planet sweeps out an <em>area C </em>from point <em>P4</em> to <em>P5, </em>that is equal to the previous area according to second kepler's law.
6d and 3d are like terms, so you take them and add them together because they're both positive. You get 9d-e-2e. -e and -2e are also like terms so you would put these together but subtract them to get 9d-3e.
