Isabella paid one of her bill late and owed a 4% late fee was 780. How much was Isabella's original bill in dollar
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Answer:
8.7% of the residuals are greater than 8 cm.
Step-by-step explanation:
We are given that the distribution of residuals is approximately normal with mean 0 cm and standard deviation 5.9 cm.
<em>Let X = distribution of residuals </em>
So, X ~ N()
The z score probability distribution is given by ;
Z = ~ N(0,1)
where, = mean residual = 0 cm
= standard deviation = 5.9 cm
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
So, percent of the residuals that are greater than 8 cm is given by = P(X > 8 cm)
P(X > 8 cm) = P( >
) = P(Z > 1.36) = 1 - P(Z
1.36)
= 1 - 0.9131 = 0.0869 or 8.7%
<em>The above probability is calculated using z table by looking at value of x = 1.36 in the z table which have an area of 0.9131. </em>
<em> </em>
Therefore, 8.7% of the residuals are greater than 8 cm.