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Tcecarenko [31]
2 years ago
13

Point T is the midpoint of RS, W is the midpoint of RT, and Z is the midpoint of WS. If the length of TZ is x, find the lengths

of the following segments in terms of x.
A) RW B) WZ C) RS D)ZS

Mathematics
1 answer:
julsineya [31]2 years ago
8 0

Let RS be y.

Given T is the midpoint of RS that is RT = TS = \frac{y}{2}

And W is the midpoint of RT,

that is RW = WT = \frac{\frac{y}{2} }{2} = \frac{y}{4}

Given Z is the mid point of WS.

That is WZ = ZS = \frac{WS}{2} = \frac{WT+TS}{2} = \frac{(\frac{y}{4} +\frac{y}{2} )}{2} =\frac{3y}{8}

Now TZ = TS-ZS = \frac{y}{2} -\frac{3y}{8}  = \frac{4y-3y}{8} = \frac{y}{8}

But TZ is given as x.

That is \frac{y}{8}  = x

            y=8x =RS.

A)length of RW = \frac{y}{4} = \frac{8x}{4} = 2x

B) length of WZ = \frac{3y}{8} =\frac{3*8x}{8} = 3x

C) length of RS = y =8x

D) length of ZS= WZ = 3x.

Image is attached for explanation.

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The graph shows the speed of a ball in free fall for 10 seconds. Which is the constant of proportionality shown in the graph?
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<u>Given</u>:

The graph shows the speed of a ball in free fall for 10 seconds.

We need to determine the constant of proportionality for the given graph.

<u>Constant of proportionality:</u>

The constant of proportionality can be determined using the formula,

\frac{y}{x}=k

Where k is the constant of proportionality.

Let us consider any of the coordinate from the graph and substitute in the formula.

Consider the coordinate (4,40) and substitute in the above formula.

Thus, we have;

\frac{40}{4}=k

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Performance task: A parade route must start And and at the intersections shown on the map. The city requires that the total dist
GaryK [48]

Answer:

Part A: The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles

Part B: For the total distance is as close to 3 miles as possible, the start point of the parade should be at the point on Broadway with coordinates (9.941, 4.970)

Part C: The coordinates of the cameras stationed half way down each road are;

For central avenue; (4, 2)

For Broadway; (7.97, 2.49)

Step-by-step explanation:

Part A: The length of the given route can be found using the equation for the distance, l, between coordinate points as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where for the Broadway potion of the parade route, we have;

(x₁, y₁) = (12, 3)

(x₂, y₂) = (6, 0)

l_1 = \sqrt{\left (0 -3\right )^{2}+\left (6-12 \right )^{2}} = 3 \cdot \sqrt{5}

For the Central Avenue potion of the parade route, we have;

(x₁, y₁) = (6, 0)

(x₂, y₂) = (2, 4)

l_2 = \sqrt{\left (4 -0\right )^{2}+\left (2-6 \right )^{2}} = 4 \cdot \sqrt{2}

Therefore, the total length of the parade route =-3·√5 + 4·√2 = 12.265 unit

The scale of the drawing is 1 unit = 0.25 miles

Therefore;

The actual length of the initial parade =0.25×12.265 unit = 3.09 miles

The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles

Part B:

For an actual length of 3 miles, the length on the scale drawing should be given as follows;

1 unit = 0.25 miles

0.25 miles = 1 unit

1 mile =  1 unit/(0.25) = 4 units

3 miles = 3 × 4 units = 12 units

With the same end point and route, we have;

l_1 = \sqrt{\left (0 -y\right )^{2}+\left (6-x \right )^{2}} = 12 - 4 \cdot \sqrt{2}

y² + (6 - x)² = 176 - 96·√2

y² = 176 - 96·√2 - (6 - x)²............(1)

Also, the gradient of l₁ = (3 - 0)/(12 - 6) = 1/2

Which gives;

y/x = 1/2

y = x/2 ..............................(2)

Equating equation (1) to (2) gives;

176 - 96·√2 - (6 - x)² = (x/2)²

176 - 96·√2 - (6 - x)² - (x/2)²= 0

176 - 96·√2 - (1.25·x²- 12·x+36) = 0

Solving using a graphing calculator, gives;

(x - 9.941)(x + 0.341) = 0

Therefore;

x ≈ 9.941 or x = -0.341

Since l₁ is required to be 12 - 4·√2, we have and positive, we have;

x ≈ 9.941 and y = x/2 ≈ 9.941/2 = 4.97

Therefore, the start point of the parade should be the point (9.941, 4.970) on Broadway so that the total distance is as close to 3 miles as possible

Part C: The coordinates of the cameras stationed half way down each road are;

For central avenue;

Camera location = ((6 + 2)/2, (4 + 0)/2) = (4, 2)

For Broadway;

Camera location = ((6 + 9.941)/2, (0 + 4.970)/2) = (7.97, 2.49).

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ElenaW [278]

Answer:

These are the rectangular prisms that have a surface area greater than 140 square feet

6 feet by 5 feet by 4 feet

7 feet by 6 feet by 4 feet

8 feet by 3 feet by 7 feet

Step-by-step explanation:

The formula to find the surface area of a rectangular prism is SA=2(wl+hl+hw)

All you have to do is go through all the options given to you to figure out which retangular prisms have a surface area greater than 140 square feet.

6 feet by 2 feet by 3 feet

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SA = 2(74)

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7 feet by 6 feet by 4 feet

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8 feet by 3 feet by 7 feet

SA = 2((8)(3)+(7)(3)+(7)(8))

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SA = 2((8)(4)+(3)(4)+(3)(8))

SA = 2(32 + 12 + 24)

SA = 2(68)

SA = 136

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2 years ago
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