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Tcecarenko [31]
2 years ago
13

Point T is the midpoint of RS, W is the midpoint of RT, and Z is the midpoint of WS. If the length of TZ is x, find the lengths

of the following segments in terms of x.
A) RW B) WZ C) RS D)ZS

Mathematics
1 answer:
julsineya [31]2 years ago
8 0

Let RS be y.

Given T is the midpoint of RS that is RT = TS = \frac{y}{2}

And W is the midpoint of RT,

that is RW = WT = \frac{\frac{y}{2} }{2} = \frac{y}{4}

Given Z is the mid point of WS.

That is WZ = ZS = \frac{WS}{2} = \frac{WT+TS}{2} = \frac{(\frac{y}{4} +\frac{y}{2} )}{2} =\frac{3y}{8}

Now TZ = TS-ZS = \frac{y}{2} -\frac{3y}{8}  = \frac{4y-3y}{8} = \frac{y}{8}

But TZ is given as x.

That is \frac{y}{8}  = x

            y=8x =RS.

A)length of RW = \frac{y}{4} = \frac{8x}{4} = 2x

B) length of WZ = \frac{3y}{8} =\frac{3*8x}{8} = 3x

C) length of RS = y =8x

D) length of ZS= WZ = 3x.

Image is attached for explanation.

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FOIL (2x+50) * (2x+70), we get

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=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

We could take approximately 12 cm.



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