For this case we have the following equation:
y = 3619000 (2.7) ^ 0.009t
We must evaluate the equation for the year 2000.
Therefore, we must replace the following value of t:
t = 2000 - 1994
t = 6
Substituting we have:
y = 3619000 (2.7) ^ (0.009 * 6)
y = 3818407.078
Round to the nearest ten thousand:
y = 3820000
Answer:
3820000 residents are living in that city in 2000
Answer:
P(t) = 27000 * (1/9)^(t/4)
Step-by-step explanation:
This problem can me modelled with an exponencial formula:
P = Po * (1+r)^t
Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.
In this problem, we have that the inicial population/value is 27000, the rate is -8/9 (negative because the population decays), and the time t is in months, so as the rate is for every 4 months, we use the value (t/4) in the exponencial.
So, our function will be:
P(t) = 27000 * (1-8/9)^(t/4)
P(t) = 27000 * (1/9)^(t/4)
For this case we must pose a verbal problem equivalent to the following expression:
So, we have:
The sum of double a number plus five.
We propose the expression:
A number subtracted from the sum of double the same number plus five equals twenty-six.
Answer:
A number subtracted from the sum of double the same number plus five equals twenty-six.
9.81 times 10 to the -5th power
Answer:
It's (C) 240in3
Step-by-step explanation:
Volume of the prototype is 250 in.³
