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nordsb [41]
2 years ago
13

A movie theater charges \$10.50$10.50dollar sign, 10, point, 50 per ticket and \$5$5dollar sign, 5 per bucket of popcorn. You ne

ver buy the popcorn because you think it's too expensive. Is the total price you pay proportional to the number of tickets you buy? Choose 1 answer:
Mathematics
2 answers:
Alika [10]2 years ago
8 0

Answer:

a in khan academy

Step-by-step explanation:

Kay [80]2 years ago
3 0

Since you never plan to buy the popcorn but only the movie ticket, therefore we can definitely say that there is a direct correlation between the total price and the number of tickets bought.

The proportion equation is:

P = 10.50 t

<span>where P is the total price and t is the number of tickets</span>

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A probability calculator is required on this problem; answer to six decimal places. Suppose we will spin the wheel pictured 400
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Answer:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

And we can find the real value with the following excel code using the binomial distribution:

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And we got 0.118 a very close value from the value obtained using the normal approximation

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=400, p=0.2)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=400*0.2=80 \geq 10

n(1-p)=400*(1-0.2)=320 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=400*0.2=80

\sigma=\sqrt{np(1-p)}=\sqrt{400*0.2(1-0.2)}=8

So then we can approximate the random variable as X \sim N(\mu = 80, \sigma = 8)

And we want this probability:

P(90< X< 110)

We can use the z score formula given by:

z = \frac{x -\mu}{\sigma}

And replacing we got:

P(90< X< 110)= P(\frac{90-80}{8}

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P(90< X< 110)=P(z

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