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2 years ago

6

an apple Orchard sells apples in bags of 10. the orchard sold a total of 2,430 apples one day. how many bags of apples was this

?

2 answers:

ANEK [815]2 years ago

7 0

243. A division problem

Alborosie2 years ago

3 0

Ok

applessold=applesperbag times bagssold
applessold=2430
applesperbag=10
bagssold=b

2430=10b
divide both sides by 10
243=b
243 bags were sold

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250 employees in an organization were surveyed about their hair color and height. The data collected is presented in the table.

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2 years ago

University graduates have a mean job search time of 38.1 weeks, with a standard deviation of 10.1 weeks. The distribution of job

Lera25 [3.4K]

Answer:

7.1 weeks to 68.4 weeks

Step-by-step explanation:

Chebyshev's Theorem states that:

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In this problem, we have that:

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Between 3 standard deviations of the mean.

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1 year ago

which equation is in slope-intercept form and represents a line with slope 3 through the point (9,-4)

krek1111 [17]

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y = mx + b

y = 3x + b

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Now, we can simplify by computing the multiplication on the right side of the equation.

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Finally, we can find the value for b by subtracting 27 from both sides of the equation to get:

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Hope this helps!

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2 years ago

Read 2 more answers

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1 year ago

A firm has a revenue function that can be represented by r (x)=700x-0.35x^2, where r (x) is the total revenue (in dollars) and x

Fudgin [204]

Answer:

How many units need to be sold to produce the maximum revenue? 1000 units

How many in dollars is the maximum revenue when the maximum of units are sold? $350,000

Step-by-step explanation:

We get max value of a function if we differentiate it and set it equal to 0.

We need to differentiate r(x) and set it equal to 0 and solve for x.

<u><em>That would be number of units sold to get max revenue.</em></u>

<u><em /></u>

<u>Then we take that "x" value and substitute into r(x) to get the max revenue amount.</u>

<u />

Before differentiating, we see the rules shown below:

$f(x)=ax^n\\f'(x)=n*ax^{n-1}$

Where

f'(x) is the differentiated function

Now, let's do the process:

$r (x)=700x-0.35x^2\\r(x)=700-2*0.35x\\r(x)=700-0.7x\\0=700-0.7x\\0.7x=700\\x=1000$

So, 1000 units need to be sold for max revenue

Now, substituting, we get:

$r (x)=700x-0.35x^2\\r(1000)=700(1000)-0.35(1000)^2\\r(1000)=350,000$

The max revenue amount is $350,000

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1 year ago