Answer:
Hypothesis rejected
Step-by-step explanation:
Lets use the t-test since the variance of the population is now known. We need to test the hypothesis that H_0: \mu \leq 79 \text{ vs } H_1: \mu > 79 . This is performed in R as follows:
t.test(tt$Test.2.Score,mu=79,alternative="greater")
One Sample t-test
data: tt$Test.2.Score
t = 2.9238, df = 69, p-value = 0.002337
alternative hypothesis: true mean is greater than 79
95 percent confidence interval:
81.26555 Inf
sample estimates:
mean of x
84.27143
Thus, we reject the null hypothesis and conclude that \mu > 79.
Answer:
C. All mathematics teachers who have taken one or more courses in statistics
Total men is 12 + 86 = 98
If 200 people were surveyed, that means the number of women should be 200 - 98 = 102.
Table B is the only one with 102 total women.
0.08(y + -1) + 0.12y = 0.14 + -0.05(10)
Reorder the terms:
0.08(-1 + y) + 0.12y = 0.14 + -0.05(10)
(-1 * 0.08 + y * 0.08) + 0.12y = 0.14 + -0.05(10)
(-0.08 + 0.08y) + 0.12y = 0.14 + -0.05(10)
Combine like terms: 0.08y + 0.12y = 0.2y
-0.08 + 0.2y = 0.14 + -0.05(10)
Multiply -0.05 * 10
-0.08 + 0.2y = 0.14 + -0.5
Combine like terms: 0.14 + -0.5 = -0.36
-0.08 + 0.2y = -0.36
Solving
-0.08 + 0.2y = -0.36
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '0.08' to each side of the equation.
-0.08 + 0.08 + 0.2y = -0.36 + 0.08
Combine like terms: -0.08 + 0.08 = 0.00
0.00 + 0.2y = -0.36 + 0.08
0.2y = -0.36 + 0.08
Combine like terms: -0.36 + 0.08 = -0.28
0.2y = -0.28
Divide each side by '0.2'.
y = -1.4
Simplifying
y = -1.4
h=5 in
w-6 in
l=12 in
SA/V=2*12*6+2*6*5+2*12*5/12*6*5
817:180
This is just an example do not use this exact equation and number! Hope it helps. : )
