<span>the correct answer is
D) 1000 kilometers </span>
<span>(x) - (0.03)(200) = 2.00
Let x be the </span><span>company charge to make the profit
solving for x gives 8$</span>
Answer:
The dimensional analysis method uses equivalences written in <u>fractional</u> form. Because the numerator and denominator of the fraction are equivalent, the value of the fraction is <u>1.</u> Multiplying by 1 does not change the quantity, but using an equivalence will change the units (or label). In order for units to cancel they must be in <u>the numerator and the denominator</u> of the fraction
Step-by-step explanation:
Dimensional analysis is a method of problem solving that takes into consideration the identity property of multiplication whereby the product of a number and 1 will always give the same number, that is 1 × n = n whereby the value "n" remains the same after the multiplication
Therefore, a fraction of two equivalent measurements but different units has a value of 1, and multiplying the equivalent fraction with another measurement with the same unit as the denominator of the fraction with a value of 1 changes the unit to that of the unit of the numerator
A` ( 7, 7 )
B ` ( 10.5, 28 )
The slope: m = (28-7) / ( 10.5 - 7 ) = 21 / 3.5 = 6
d ( A` B `) = √ ( 10.5 - 7 )² + ( 28 - 7 )² = √ 3.5² + 21² =
= √ 12.25 + 441 = √ 12.25 ( 1 + 36 ) = 3.5 √37 ( or 3.5 * (37) ^(1/2))
Answer:
C ) m = 6, A`B` = 3.5√37
Answer:
The value of q that maximize the profit is q=200 units
Step-by-step explanation:
we know that
The profit is equal to the revenue minus the cost
we have
---> the revenue
---> the cost
The profit P(q) is equal to
substitute the given values
This is a vertical parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
The x-coordinate of the vertex represent the value of q that maximize the profit
The y-coordinate of the vertex represent the maximum profit
using a graphing tool
Graph the quadratic equation
The vertex is the point (200,-120)
see the attached figure
therefore
The value of q that maximize the profit is q=200 units
