Question

How do I write log7t as a base 2 logarithm?

Answer 1

Answer:

log2t/log2^7

Step-by-step explanation:

(what the other dude said)

Answer 2

Given:

The value is $\log_7t$.

To find:

The value as a base 2 logarithm.

Solution:

We know that,

$\log_xy=\dfrac{\log_ay}{\log_ax}$

where, a is any positive value.

We have,

$\log_7t$

Using the above property of logarithm, we get

$\log_7t=\dfrac{\log_at}{\log_a7}$

For a=2,

$\log_7t=\dfrac{\log_2t}{\log_27}$

Therefore, the given value as a base 2 logarithm can be written as $\dfrac{\log_2t}{\log_27}$.