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2 years ago

For each system of equations, drag the true statement about its solution set to the box under the system?

Mathematics

1 answer:

natta225 [31]2 years ago

3 0

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

coefficients of x and y are the same and the numerical terms

are the same

- The system of equation has one solution if at least one of the

coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

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substitute

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substitute:

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1 year ago

Let X represent the amount of time until the next student will arrive in the library parking lot at the university. If we know t

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Answer:

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Step-by-step explanation:

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$=0.25\times \int\limits^{\infty}_{10}{e^{-0.25x}}\, dx\\=0.25\times |\frac{e^{0.25x}}{-0.25}|^{\infty}_{10}\\=(e^{-0.25\times \infty})-(e^{-0.25\times 10})\\=0.0821$

Thus, the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

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2 years ago

Suppose bug A lands on the end of the blade farthest from the pivot. Assume the wiper turns through an angle of 120°. In one cyc

ruslelena [56]

Answer:

s = 21.33*π in

Step-by-step explanation:

Given:

- The complete data is given in the figure (attached):

Solution:

- The bugs lands on the end of the wiper blade furthest to the pivot. The arc length (s) swept by a wiper in one cycle i.e θ = 120° would be given by:

s = 2*r*θ

- Where, r: The distance between the bug and the pivot = 16 in

θ : Angle swept in radians

- The distance travelled by the bug is s:

s = 2*(16)*( 120 / 180 ) * π

s = 21.33*π in