D is the best choice because y would be the total amount of money he would have to pay. X would be the amount of hours he uses the phone and the hourly fee is 23 so it would be 23x. the flat fee was 16 so you just add that on to the hourly fee. The whole equation should be y = 23x + 16
Answer:
a kite has 2 short sides and 2 long sides. The 2 short sides are equal. The 2 long sides are also equal. This means that the other short side is 16cm. And the remaining longer sides can be found like this:
let's pretend *y* is the long side
2*y = 70 - 16 - 16. (two of the long sides = 70 - short side - another short side)
so use algebra to find y.
2*y = 38
y = 19 so the long sides are both 19cm each
Your final answer: 16cm, 19cm, 19cm
Answer:
a) density of the object is 3995.01, b) the weight scale reads 22N c) the sum individually will be the same with when added together.
Step-by-step explanation:
The weight of the object in air is 8N,
and weight = Mass * acceleration due to gravity = m * 9.81
8/9.81 = 0.815,
upthrust( force acting on the body from the liquid impeding the immersion) on the body when fully submerged = weight in air - weight in water = 8N - 6N =2N
Upthrust = weight of water displaced = 2N = mass * acceleration
2/9.81 = 0.204kg
density of water(1000kg/m^3) = mass of water / volume of water
volume of water displaced = 0.204/1000 = 0.000204m^3 (204cm^3)
volume of water displaced = volume of the solid
density of solid = mass/ volume = 0.815/0.000204 = 3995.01kg/m^3
b) when fully submerge in water the the scale experience according to newton third law of motion ( equal and opposite reaction of forces) additional 2N push so that total weight with the fully submerge solid = 20N + upthrust = 20N + 2N =22N
c) the of two scale reading is before (8N + 20N = 28N) and after (6N + 22N = 28) since there is no loss of matter; the demonstration was in equilibrium.
Answer:
1. Car B is moving east at 70MPh and is in from of car A
2.car B is moving west at 70 mph and is behind car A
Step-by-step explanation:
Use the cardinal point system to evaluate the problem first
