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3241004551 [841]
2 years ago
12

Direct Mailing Company sells computers and computer parts by mail. The company claims that more than 90% of all orders are maile

d within 72 hours after they are received. The quality control department at the company often takes samples to check if this claim is valid. A recently taken sample of 175 orders showed that 161 of them were mailed within 72 hours. Do you think the company’s claim is true? Use the 1% significance level. What type of problem is this?
Mathematics
1 answer:
lys-0071 [83]2 years ago
6 0

Answer:

We conclude that less than or equal to 90% of all orders are mailed within 72 hours after they are received which means the company's claim is not true.

Step-by-step explanation:

We are given that the company claims that more than 90% of all orders are mailed within 72 hours after they are received. The quality control department at the company often takes samples to check if this claim is valid.

A recently taken sample of 175 orders showed that 161 of them were mailed within 72 hours.

<u><em>Let p = percentage of all orders that are mailed within 72 hours.</em></u>

SO, Null Hypothesis, H_0 : p \leq 90%   {means that less than or equal to 90% of all orders are mailed within 72 hours after they are received}

Alternate Hypothesis, H_A : p > 90%   {means that more than 90% of all orders are mailed within 72 hours after they are received}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = proportion of orders that were mailed within 72 hours in a sample of 175 =  \frac{161}{175}\times 100  = 92%

           n = sample of orders = 175

So, <u><em>test statistics</em></u>  =  \frac{0.92-0.90}{{\sqrt{\frac{0.92(1-0.92)}{175} } } } }

                               =  0.975

The value of the test statistics is 0.975.

<em>Now at 1% significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is less than the critical value of z as 0.975 < 2.3263, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that less than or equal to 90% of all orders are mailed within 72 hours after they are received which means the company's claim is not true.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Z=\dfrac{37.4-24.4 }{6.5 } = 2

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b) From the z-score table, the probability that the commute time to be less than 11.4 minutes = The probability at z = -2 = 0.02275

c) From the z-score table, the probability that the commute time to be greater than 37.4 minutes = The probability at z = 2 = 0.97725

Q2 The the z-score that corresponds to a commute time of 15 minutes is given as follows;

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