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musickatia [10]
2 years ago
10

The transportation department has to put a railing along the outer curve of this road. The road is 20 feet wide. What is the len

gth of the outer curve to the nearest foot? Use the value Pi= 3.14..

Mathematics
2 answers:
Dovator [93]2 years ago
6 0
From my research, the image attached supports the problem. Since only the outer curve is to be solved for, the formula for arcs can be used.

s = theta*radius

where s = arc length = outer curve

theta = 70 (pi/180)
radius = 70

s = 70 * (70*pi/180)
s = 85.52 feet

Therefore, the outer curve is 85.52 feet long

lara [203]2 years ago
4 0

Answer: Your answer should be 86 feet :)

Hope this helps ❤️

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sammy [17]
Eight graders is the answer
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The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min
Deffense [45]

Answer:

a

    f'(t) is  negative

b

 The  unit is degC/min

c

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.          

Step-by-step explanation:

From the question we are told we are told that  

   The  equation for the temperature of a cup of coffee place on a counter is

         H= f(t)

Here  t is the time in minutes the  coffee was put on the counter

Generally  f(t)'  is the derivative of  f(t) at it represents the change of the temperature of the cup of coffee with respect to time

 Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence  f(t)' is  negative

Generally the unit of the temperature is in degrees Celsius while that of time is  in minutes

  So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e  degC/min)

  From the question we are told that

        |f(35)'| =  1.5

i.e  the rate of change of temperature after 35 minutes is  1.5

and

         |f(35)| =  68

i.e the temperature of the cup of coffee after 35 minutes is  67 degC

Now after another   t=  30  seconds =  \frac{30}{60}= 0.5 \ minutes the  rate  of change of the temperature of the cup of  coffee is  

          R =  |f(35)'| *  t

=>        R = 1.5  *  0.5

=>        R = 0.75    

So

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.  

     

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