Answer:
The width of lot B is 11 feet, so option A is correct.
Step-by-step explanation:
Given:
- Two rectangular properties share a common side.
- Lot A is 33 feet wide and 42 feet long.
- The combined area of the lots = 1,848 square feet.
To find:
How many feet wide is Lot B?
Solution:
we know that, area of a rectangle is length x breadth
Then area of lot A = 33 x 42 = 1386 square feet.
And area of lot B = width x 42
Now, we are given that, total area = 1848
area of lot A + area of lot B = 1848
1386 + width x 42 = 1848
width x 42 = 1848 – 1386
width x 42 = 462
width = 11
Hence, the width of lot B is 11 feet, so option A is correct.
B. every member of the boys' basketball team
because people who play basketball are generally taller which means they have bigger feet (most of the time) which doesn't accurately represent the average of the male student body.
Answer:
c
Step-by-step explanation:
C=90°, A=75°, b=AC=19, x=AB
Without a figure, we see AC is adjacent to angle A, so
cos A = AC/AB = b/x
x = b/cos A = 10 / cos 75° ≈ 38.637
Answer: 38.6
1)
.
2)
.
3) The particle is moving right when the velocity function is positive:
or
.
4) When
the particle is slowing down because the acceleration is close to zero
the particle is speeding up when acceleration is increasing away from zero:
.
5)
.
