Answer:
The value of q that maximize the profit is q=200 units
Step-by-step explanation:
we know that
The profit is equal to the revenue minus the cost
we have
---> the revenue
---> the cost
The profit P(q) is equal to

substitute the given values



This is a vertical parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
The x-coordinate of the vertex represent the value of q that maximize the profit
The y-coordinate of the vertex represent the maximum profit
using a graphing tool
Graph the quadratic equation
The vertex is the point (200,-120)
see the attached figure
therefore
The value of q that maximize the profit is q=200 units
Answer:
See below.
Step-by-step explanation:
Well first, we need to find the weight of the table. We know that 8 boxes weighs a total of 240kg (since each box weights 30kg). Thus, we can conclude that the table weighs 70kg by doing 310-240=70.
Now, we can write our function. Let
equal the amount of boxes.
The table is a set weight, so that would be our constant.
Thus, we will have:

30x represents the weight each box of book adds to the total. One box equals 30kg, 2 boxes equal 60kg, etc.
The 70 represents the unchanging weight of the table.
In terms of W(x), it will be:

Answer:
The standard error of the proportion is 0.0367.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the standard error is 
In this question:

So

The standard error of the proportion is 0.0367.
Answer: From what you wrote the I think the ball is drop
At time 0 you are 7 meters above ground
You basically just need to solve for
1.5 =7t-4.9t^2
by rearrange the equation you get
4.9t^2-7t+1.5=0
by using Quadratic Formula
t=1.166s