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vitfil [10]
1 year ago
7

A baker uses a coffee mug with a diameter of 8 cm 8 cm8, start text, space, c, m, end text to cut out circular cookies from a bi

g sheet of cookie dough. What is the area A AA of each cookie? Give your answer in terms of pi.
Mathematics
2 answers:
katrin2010 [14]1 year ago
7 0

Answer:

8 in terms of pi

Step-by-step explanation:

because i did kahn academy

horsena [70]1 year ago
3 0

Answer:

Step-by-step explanation:

The diameter of the top of the coffee mug which the baker uses to cut out circular cookies from the big sheet of cookie dough is 8 cm.

Radius of the coffee mug is diameter of the coffee mug/2.

Radius of the coffee mug

= 8/2 = 4cm

The area of the circular mug is expressed as

Area = πr^2

Where π is a constant whose value is 3.14

Therefore,

Area of the top of the circular mug = 3.14 × 4^2 = 3.14 × 16 = 50.24 cm^2

The area of the top of the circular cup is the same as the area of each cookie. Therefore,

The area of each cookie is 50.24 cm^2

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Answer:

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Step-by-step explanation:

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jenyasd209 [6]

Answer:

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Step-by-step explanation:

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One factor of the function f(x) = x3 − 8x2 + 17x − 10 is (x − 5). Describe how to find the x-intercepts and the y-intercept of t
kozerog [31]

Answer:

x-intercepts: (1,0), (2,0), (5,0)

y-intercepts: (0,-10)

Step-by-step explanation:

One factor of the function f(x) = x^3-8x^2 + 17x-10 is (x-5).

Factor the polynomial in the following way:

x^3-8x^2 + 17x-10\\ \\=x^3-5x^2-3x^2+15x+2x-10\\ \\=x^2(x-5)-3x(x-5)+2(x-5)\\ \\=(x-5)(x^2-3x+2)

Now factor the quadratic in brackets:

x^2-3x+2\\ \\=x^2-2x-x+2\\ \\=x(x-2)-(x-2)\\ \\=(x-2)(x-1)

Hence,

f(x)=(x-5)(x-2)(x-1)

The x-intercepts are points at which y = 0, so

(x-5)(x-2)(x-1)=0\\ \\x-5=0\ \text{or}\ x-2=0\ \text{or}\ x-1=0\\ \\x=5\ \text{or}\ x=2\ \text{or}\ x=1

The y-intercepts are points at which x = 0, so

y=0^3-8\cdot 0^2+17\cdot 0-10=-10

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Her tax will be $8,306
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