The only ones that would work are if the factor is composite and if 1 is added to it it can be divided into 48. So 15 would work. The factor 15 is composite, and if 1 is added it can be divided into 48.Therefore the son is 15.
Let us see... ideally we would like to have all equations with the same exponent or the same base so that we can compare the rates. Since the unknown is in the exponent, we have to work with them. In general,
![x^(y/z)= \sqrt[z]{x^y}](https://tex.z-dn.net/?f=x%5E%28y%2Fz%29%3D%20%5Csqrt%5Bz%5D%7Bx%5Ey%7D%20)
.
Applying this to the exponential parts of the functions, we have that the first equation is equal to:
250*(
![\sqrt[5]{1.45} ^t](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B1.45%7D%20%5Et)
)=250*(1.077)^t
The second equation is equal to: 200* (1.064)^t in a similar way.
We have that the base of the first equation is higher, thus the rate of growth is faster in the first case; Choice B is correct.
NO!
Prove by contradiction. First, define the the following terms:
odd function: f(-x) = -f(x)] and domain: all values of x
Proof: Suppose there f(-x) = -f(x) such that x is a negative integer, then f(-x) is a positive number <em>(-(-x) = +x)</em> and -f(x) is a negative number <em>(negative of a positive number is a negative number). </em>Since a positive number cannot equal a negative number, then this is not possible.
Answer: No
Answer:
Step-by-step explanation:
The sample space is known to be the set of all possible outcomes of an experiment we cannot predict its outcome while the event space showcases the subset of the sample space, this may be a collection of outcomes of a random experiment.
From the given information:
The sample space = {SH, SL, SN, MH, ML, MN,UH, UL, UN}
The event that the emissions check is satisfactory = {SH, SL, SN}