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Harrizon [31]
2 years ago
7

During a snowstorm, Alang tracked the amount of snow on the ground. When the storm began, there was no snow on the ground. For t

he first 2 hours of the storm, snow fell at a constant rate of 1 inch per hour. The storm then stopped for 6 hours and then started again at a constant rate of 3 inches per hour for the next 5 hours. Make a graph showing the inches of snow on the ground over time using the data that Alang collected.
Mathematics
1 answer:
Pachacha [2.7K]2 years ago
4 0

Answer:

over specific intervals. TO GRAPH PIECEWISE FUNCTIONS: 1. Create a ... function. 2. Plot correct points (if more are plotted than are required points are ... EX 6: During a snowstorm, a meteorologist tracks the amount of accumulating ... the first three hours of the storm, the snow fell at a constant rate of one inch per hour.

Step-by-step explanation:

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9400 dollars is placed in an account with an annual interest rate of 6.25%. To the nearest tenth of a year, how long will it tak
liubo4ka [24]

Answer:

t=64.2\ years

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=?\ years\\ P=\$9,400\\ A=\$47,100\\r=6.25\%=6.25/100=0.0625

substitute in the formula above

47,100=9,400(1+0.0625t)

solve for t

t=[(47,100/9,400)-1]\0.0625

t=64.2\ years

6 0
2 years ago
Justin recently started working for a company that pays him $11.40 per hour. He is expected to work a total of 251 days for 8 ho
Serhud [2]

Answer:

22,891.20

Step-by-step explanation:

I took this quiz and got it right.

6 0
2 years ago
Read 2 more answers
The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat
Greeley [361]

Answer:

1) L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

2) T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

3) T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

Part 2

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

Part 3

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

Replacing we got:

T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

8 0
2 years ago
A brochure from the department of public safety in a northern state recommends that motorists should carry 12 items (flashlights
scoray [572]

Answer:

Mean = 6.07

Median = 7

Mode = 7

Step-by-step explanation:

Given

Data: 5\ 3\ 7\ 8\ 0\ 1\ 0\ 5\ 12\ 10\ 7\ 6\ 7\ 11\ 9

n = 15

Solving (a): The mean

Mean is calculated as:

Mean = \frac{\sum x}{n}

This gives:

Mean = \frac{5+ 3+ 7+ 8+ 0+ 1+ 0+ 5+ 12+ 10+ 7+ 6+ 7+ 11+ 9}{15}

Mean = \frac{91}{15}

Mean = 6.07

Solving (b): The median

Sort the data in ascending order:

Data: 5\ 3\ 7\ 8\ 0\ 1\ 0\ 5\ 12\ 10\ 7\ 6\ 7\ 11\ 9

Sorted: 0\ 0\ 1\ 3\ 5\ 5\  6\ 7\ 7\ 7\ 8\ 9\ 10\ 11\ 12

The median is:

Median = \frac{n + 1}{2}th

Median = \frac{15 + 1}{2}th

Median = \frac{16}{2}th

Median = 8th    

The 8th item on the sorted dataset is 7; So:

Median = 7

Solving (c): The mode

Mode = 7

Because it has a frequency of 3 (more than any other element of the dataset).

6 0
2 years ago
Complete the steps for solving 7 = –2x2 + 10x. Factor out of the variable terms. inside the parentheses and on the left side of
Mamont248 [21]

we have

7=-2x^{2} +10x

Factor the leading coefficient

7=-2(x^{2} -5x)

Complete the square. Remember to balance the equation by adding the same constants to each side

7-12.50=-2(x^{2} -5x+2.5^{2})

-5.50=-2(x^{2} -5x+2.5^{2})

Divide both sides by -2

2.75=(x^{2} -5x+2.5^{2})

Rewrite as perfect squares

2.75=(x-2.5)^{2}

Taking the square roots of both sides (square root property of equality)

x-2.5=(+/-)\sqrt{2.75}

Remember that

\sqrt{2.75}=\sqrt{\frac{11}{4}}= \frac{\sqrt{11}}{2}

x-2.5=(+/-)\frac{\sqrt{11}}{2}

x=2.5(+/-)\frac{\sqrt{11}}{2}

x=2.5+\frac{\sqrt{11}}{2}=\frac{5+\sqrt{11}}{2}

x=2.5-\frac{\sqrt{11}}{2}=\frac{5-\sqrt{11}}{2}

<u>the answer is</u>

The solutions are

x=\frac{5+\sqrt{11}}{2}

x=\frac{5-\sqrt{11}}{2}


5 0
2 years ago
Read 2 more answers
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