Answer:
A) The probability that the event will occur
B)The probability that the event will not occur =
Step-by-step explanation:
We are given that The odds of event occurring are 1:6.
So, Number of successful events = 1
Number of unsuccessful events = 6
So, Total events = 6+1=7
a)the probability that the event will occur=
The probability that the event will occur
b)The probability that the event will not occur =
The probability that the event will not occur =
Answer:
The product is
Step-by-step explanation:
To do this we must understand how the basic operations apply to powers. If the power has the same base and we multiply them, the base remains the same while we sum the powers, if we divide them the base remains the same and we subtract the powers, if we try to make a power of a power the two powers multiply. Applying this rule we have:
Answer:
Comparing the p value with a significance level for example we see that
so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.
Step-by-step explanation:
Data given
Campus Sample size Mean Population deviation
1 330 33 8
2 310 31 7
represent the mean for sample 1
represent the mean for sample 2
represent the population standard deviation for 1
represent the population standard deviation for 2
sample size for the group 1
sample size for the group 2
Significance level provided
z would represent the statistic (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:
(1)
z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.
With the info given we can replace in formula (1) like this:
P value
Since is a one right tailed test the p value would be:
Comparing the p value with a significance level for example we see that
so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.
Answer:
(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).
(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).
(c) First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).
Step-by-step explanation:
(a)
Let <em>X</em> = number of dog owners who take more pictures of their dog than of their significant others or friends.
Given:
<em>X</em> = 610
<em>n</em> = 1000
Confidence level = 90%
The (1 - <em>α</em>)% confidence interval for population proportion is:
The sample proportion is:
The critical value of <em>z</em> for a 90% confidence level is:
Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:
Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).
<u>Interpretation</u>:
There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).
Correct option is (3).
(b)
Let <em>X</em> = number of dog owners who are more likely to complain to their dog than to a friend.
Given:
<em>X</em> = 440
<em>n</em> = 1000
Confidence level = 95%
The (1 - <em>α</em>)% confidence interval for population proportion is:
The sample proportion is:
The critical value of <em>z</em> for a 95% confidence level is:
Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:
Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend is (0.42, 0.46).
<u>Interpretation</u>:
There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).
Correct option is (1).
(c)
The confidence interval in part (b) is wider than the confidence interval in part (a).
The width of the interval is affected by:
The confidence level in part (b) is more than that in part (a).
Because of this the critical value of <em>z</em> in part (b) is more than that in part (a).
Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.
First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).
Answer:
Step-by-step explanation:
Let consider that door has a height of 5 feet and a width of 3 feet. The scale factor is:
The height of the cabinet is: