Answer:
Probability that at most 50 seals were observed during a randomly chosen survey is 0.0516.
Step-by-step explanation:
We are given that Scientists conducted aerial surveys of a seal sanctuary and recorded the number x of seals they observed during each survey.
The numbers of seals observed were normally distributed with a mean of 73 seals and a standard deviation of 14.1 seals.
Let X = <u><em>numbers of seals observed</em></u>
The z score probability distribution for normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean numbers of seals = 73
= standard deviation = 14.1
Now, the probability that at most 50 seals were observed during a randomly chosen survey is given by = P(X
50 seals)
P(X
50) = P(
) = P(Z
-1.63) = 1 - P(Z < 1.63)
= 1 - 0.94845 = <u>0.0516</u>
The above probability is calculated by looking at the value of x = 1.63 in the z table which has an area of 0.94845.
Answer:
126 feets
Step-by-step explanation:
Given that :
Equation of line repressing nature trail :
y = 13x - 4
Distance of gazebo from nature trail :
Each unit in coordinate plane = 10 feets
Hence,
y = 13(10) - 4
y = 130 - 4
y = 126 feets
Answer:
she should have x-27 books left
Step-by-step explanation:
1. You have the following information:
-The annual interest rate <span>is 7.2%.
- The </span><span>simple interest is calculated quarterly.
2. Then, to solve this exercise and calculate the </span><span>periodic interest rate of Marta's Account, you only have to divide the annual interest rate (7.2%) by 1/4 year. So, you have:
</span>
=(7.2%)(1/4)
=(7.2%)/4
=1.8%
<span>What is the periodic interest rate of Marta's Account?
The answer is: </span>1.8%