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ad-work [718]
2 years ago
7

Monique planted seeds to grow pansies, Snapdragons, and petunias. After several weeks, 18 out of 40 pansy seeds, 21 out of 50 sn

apdragon seeds, and 12 out of 30 petunia seeds grew into plants. Write the named of the plants in order from least percentage of plants that grew to the greatest percentage of plants that grew.
Mathematics
2 answers:
OLEGan [10]2 years ago
7 0

Answer:

petunias, snapdragons, then pansy

Step-by-step explanation:

Ok first, lets find the percentage of 18 out of 40: 18/40= 0.45

The 21 out of 50= 21/50= 0.42

Lastly, 12/30= 0.40

And its very simple to put from least to greatest:

0.40, 0.42, 0.45

Hope this helped ;)

nignag [31]2 years ago
6 0

The answer is petunias, snapdragons, then pansies.

Hope this helps!

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ABCD is a parallelogram. E is the point where the diagonals AC and BD meet. Prove that triangle ABE is congruent to triangle CDE
Darina [25.2K]
ABCD is a parallelogram                  Given
AE=CE, BE=DE                                <span>The diagonals of a parallelogram are                                                                     bisect each other
</span>∠AEB=∠CED                                    Vertical angles are congruent
ΔABE is congruent to ΔCDE            SAS theorem<span>
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5 0
2 years ago
Read 2 more answers
Lin knows that there are 4 quarts in a gallon. She wants to convert 6 quarts to a gallon, but cannot decide if she should multip
defon

Given:

There are 4 quarts in a gallon.

She wants to convert 6 quarts to a gallon.

To find:

Whether she should multiply 6 by 4 or divide 6 by 4 to find her answer.

Solution:

We have,

4\text{ quarts}=1\text{ gallon}

1\text{ quarts}=\dfrac{1}{4}\text{ gallon}

6\text{ quarts}=\dfrac{6}{4}\text{ gallon}

Here, 6 quarts is equal to \dfrac{6}{4} gallon. It means we need to multiply 6 by 4 in 4\text{ quarts}=1\text{ gallon} to find the answer.

5 0
2 years ago
Here is a scale drawing of a window frame that uses a scale of 1 cm to 6 inches.Create another scale drawing of the window frame
Tresset [83]

Answer:

Step-by-step explanation:

Below is the rectangle in the attachment.

Current scale:

1 cm : 6 inches

If the dimensions of the rectangle is:

Length = a cm

Width = b cm

Using the scale:

Length = a × 6 inches

Width = b × 6 inches

Using the same dimensions of the rectangle is:

Length = a cm

Width = b cm

Using the scale:

Length = a × 12 inches

Width = b × 12 inches

Note that there is an enlargement of the rectangle to form the new rectangle. The length and width of new rectangle drawn will be 2 × the length and width of the rectangle seen below.

8 0
2 years ago
Find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Let x, y, and z be the dimensions of the box
Gala2k [10]

Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

Volume of box =xyz=1728

z=\frac{1728}{xy}

Surface area of box = 2xy+2yz+2xz=2xy+2y(\frac{1728}{xy})+2x(\frac{1728}{xy})

Let f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})

To get minimal surface area

\frac{\partial f}{\partial x}=0 and \frac{\partial f}{\partial y}=0

\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial x}=0

2y-2(\frac{1728}{x^2})=0

y=\frac{1728}{x^2} ----1

\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0

2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2}  \\y^2=\frac{1728}{x}

Using 1

(\frac{1728}{x^2} )^2=\frac{1728}{x}

x=0 and x^3=1728

Side can never be 0

So,x^3=1728

x=12

y=\frac{1728}{x^2} \\y=\frac{1728}{12^2}

y=12

z=\frac{1728}{xy}\\z=\frac{1728}{(12)(12)}

z=12

The dimensions of the box are 12 cm , 12 cm , 12 cm

5 0
2 years ago
Two parallel lines are intersected by a third line so that angles 1 and 5 are congruent. 2 parallel horizontal lines are interse
densk [106]

Answer:

"They are supplementary" ⇒ last answer

Step-by-step explanation:

* <em>Look to the attached figure</em>

- Two parallel horizontal lines are intersected by a third line

- The angles formed form intersection are labeled on the figure

- From the two parallel lines and  

 ∠5 ≅ ∠1 ⇒ corresponding angles

 m∠5 = m∠1

- A linear pair is two angles that are adjacent and form a line and

 they are supplementary

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* <em>lets prove that ∠3 and ∠5 are supplementary</em>

∵ m∠1 = m∠5 ⇒ corresponding angles

∵ ∠1 and ∠3 form a linear pair

∵ Linear pair are supplementary

∴ m∠1 + m∠3 = 180°

- By substitute ∠1 by ∠5

∴ m∠5 + m∠3 = 180

∴ ∠5 and ∠3 are supplementary

* The true statement is "They are supplementary"

8 0
1 year ago
Read 2 more answers
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