Question

Given RT below, if S lies on RT such that the

Answer 1

Answer:

(-2, -3)

Step-by-step explanation:

If a segment having extreme ends as $(x_1,y_1)$ and $(x_2,y_2)$ is divided by a point (x, y) in the ratio of m:n,

x = $\frac{mx_2+nx_1}{m+n}$

y = $\frac{my_2+ny_1}{m+n}$

Since, a line RT has extreme ends as R(-5, 3) and T(-1, -5) then a point S(x, y) which divides RT in the ratio of 3 : 1 will be,

x = $\frac{3(-1)+1(-5)}{3+1}$

  = $\frac{-8}{4}$

  = -2

y = $\frac{3(-5)+1(3)}{3+1}$

  = $-\frac{12}{4}$

  = -3

Therefore, coordinates of the point S will be (-2, -3).