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Maru [420]
2 years ago
11

n ΔXYZ, m∠X = 90° and m∠Y = 30°. In ΔTUV, m∠U = 30° and m∠V = 60°. Which is true about the two triangles? ΔXYZ ≅ ΔTUV ΔXYZ ≅ ΔVU

T No congruency statement can be made because only two angles in each triangle are known. No congruency statement can be made because the side lengths are unknown.
Mathematics
2 answers:
Nikolay [14]2 years ago
6 0

Answer:

<em><u>D. No congruency statement can be made because the side lengths are unknown.</u></em>

Step-by-step explanation:

I JUST TOOK THE TEST!!!!

lions [1.4K]2 years ago
5 0
The triangles are similar because corresponding angles are congruent, however no congruency statement can be made because the side lengths are unknown.

The 4th selection is appropriate.
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7 0
2 years ago
Read 2 more answers
Sarah is planning to spend a week at her friend's summer house in Miami Beach. All meals will be provided by her friend's parent
Rus_ich [418]

Answer:

500$

Step-by-step explanation:

5 0
2 years ago
An item regularly priced at $80 is on sale for 20% off. There is a 3% sales tax.
Katena32 [7]

Answer:$14.08 and the discount is $16

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6 0
2 years ago
The diagram shows the cross section of a cylindrical pipe with water lying in the bottom.
disa [49]
Hey 

So my brother posted this on Yahoo 
Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth. A right-angled triangle is formed. Length of side to the water-surface is 5 cm, the hypot is 7 cm. 

<span>What you do now is the following: </span>

<span>Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7) </span>

<span>So θ is approx 44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8° </span>

<span>The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram. </span>

<span>Shaded area ≃ 88.8/360*area of circle - ½*7*7*sin88.8° </span>
<span>= 88.8/360*π*7² - 24.5*sin 88.8° </span>
<span>≃ 13.5 cm² </span>
<span>(using area of ∆ = ½.a.b.sin C for the triangle) </span>



<span>b) </span>

<span>volume of water = cross-sectional area * length </span>
<span>≃ 13.5 * 30 cm³ </span>
<span>≃ 404 cm³</span>

Hoped it Helped
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1 year ago
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20 I think because 8+12
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2 years ago
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