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2 years ago

7.1x10^-2 as an ordinary number

1 answer:

3 0

Hey there,

So let's start off with one part of this equation . . .

$10^{-2}$ would be 0.01.

So, we have 0.01 has our answer (so far).

Then we would do 7.1 × 0.01, this would give us . . .

0.071.

Your correct and final answer would be $\boxed{0.071}$

Hope this helps you!

~Jurgen

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kati45 [8]

2.5y + 1.1x ∠ 10

2.5y = - 1.1x +10

y = (- 1.1/2.5)x + 4

Draw this function. It's descending (m negative). All values on the left of the lines satisfy this inequality

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2 years ago

Which expression is equivalent to \left(3^{-6}\times 3^{3}\right)^{-1}\normalsize?(3 −6 ×3 3 ) −1 ? 3^{-19}3 −19 3^{18}3 18 3^{-

mars1129 [50]

Answer:

Step-by-step explanation:

Given the expression

$\left(3^{-6}\times 3^{3}\right)^{-1}\\$

According to law of indices, this can be written as;

$\left(3^{-6+3})^{-1}\\\\= (3^{-3})^{-1}\\\\= 3^{-3*-1}\\\\= 3^3\\\\= 27$

Hence the required answer is 27

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1 year ago

The quotient of 38 times a number and -4

nikdorinn [45]

Answer:

140y

Step-by-step explanation:

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4 0

1 year ago

Triangle ABE is similar to triangle ACD. AED and ABC are straight lines. EB and DC are parallel. AE = 5 cm, BC = 4.5 cm, BE = 4

lianna [129]

Answer:

y = 16x/65

Step-by-step explanation:

Given:

Triangle ABE is similar to triangle ACD. AED and ABC are straight lines

EB and DC are parallel

The area of quadrilateral BCDE = xcm²

The area of triangle ABE = ycm²

Find attached the diagram from the above information.

In similar triangles, the ratio of their corresponding angles are equal.

Also, the ratio of the area of the two triangles = square of ratio of the corresponding sides of the two triangles.

Area ∆ACD/area of ∆ABE = (DC/EB)²

Area ∆ACD/area of ∆ABE = [(area of quadrilateral BCDE +

area of ∆ABE)]/(area of ∆ABE)

(x+y)/y = (DC/EB)²

(x+y)/y = (9/4)²

x+y = (81/16)y

x = (81/16)y - y

x = (81y - 16y)/16

x = 65y/16

Making y subject of formula

16x = 65y

y = 16x/65

An expression for y in terms of x:

y = 16x/65

3 0

1 year ago

What additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS? Check all that apply.

Maksim231197 [3]

Answer: ∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.

Step-by-step explanation:

Given: ΔXYZ and ΔEFG such that ∠X=∠F

To prove they are congruent by using ASA or AAS conruency criteria

we need only one angle and side.

1. ∠Z ≅ ∠G(angle) and XZ ≅ FG(side)

so we can apply ASA such that ΔXYZ ≅ ΔFEG.

2. ∠Z ≅ ∠G (angle)and ∠Y ≅ ∠E (angle), we need one side which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.

3. XZ ≅ FG (side) and ZY ≅ GE (side), we need one angle which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.

4. XY ≅ EF(side) and ZY ≅ FG(side), not possible.

5. ∠Z ≅ ∠G(angle) and XY ≅ FE(side),so we can apply ASA such that

ΔXYZ ≅ ΔFEG.

4 0

2 years ago

Read 2 more answers