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1 year ago

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Exactly 240 years ago students planted a tree in front of their school since did the tree has grown 30 beers taller and the dist

ance around the trunk has increased three beers describe how you could find this information define at least two different unit rates

1 answer:

alexandr1967 [171]1 year ago

5 0

Ok so the units will be taller if u mix it with water

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the scale on a map is stated as 1:250000 two villages are 9 cm apart on the map how far from each other are the two villages in

Karolina [17]

Answer:

22.5 kilometers

Step-by-step explanation:

we know that

The scale drawing is

$1:250,000$

That means

1 unit on a map represent 250,000 units in the actual

or

1 cm on a map represent 250,000 cm in the actual

or

1 cm on a map represent 2,500 m in the actual

or

1 cm on a map represent 2,5 km in the actual

therefore

using proportion

Find out how much represent 9 cm apart on the map

$\frac{1}{2.5}\ \frac{cm}{km}=\frac{9}{x}\ \frac{cm}{km}\\\\x=9(2.5)\\\\x=22.5\ km$

7 0

1 year ago

If Jose earns $1700 this year selling T-shirt’s he screen prints in his garage what taxes would he need to pay?

Marta_Voda [28]

Answer:

State sales and income tax

Step-by-step explanation:

He pays income tax based on the $1700 he got when running his own business of selling T-shirt’s he screen prints in his garage and he also needs to pay for the State sales tax on each T-shirt sold to the state that his business is located in.

Hope it will find you well

3 0

1 year ago

Read 2 more answers

Which of the following is the expansion of (3c + d2)6?

vovangra [49]

Answer: Option A) $729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$ is the correct expansion.

Explanation:

on applying binomial theorem, $(a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r$

Here a=3c, $b=d^2$ and n=6,

Thus, $(3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r$

⇒ $(3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6$

⇒ $(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}$

⇒ $(3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}$

⇒ $(3c+d^2)^6=729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$

3 0

2 years ago

Read 2 more answers

Jack bought 4 dozen eggs at $10 per dozen. 6 were broken. what percent of his money goes to waste

Korvikt [17]

So, if he has 4 dozen eggs, ten dollars per dozen, he has spent $40 on 48 eggs. <em>This means the cost of one egg = 48/40. </em>This can simplify to <em>6/5 </em>which is equal to<em> $1.20. </em>This means the value of one egg is $1.20, including the broken ones! So if six were broken, we multiply 1.20 x 6 which equals <em>$7.20!</em>

Use this "formula" to help find percentages

<em>Part/Total = %( Percentage )/ 100</em>

Now that we know how much money has gone to waste, we can plug in the known values into this "formula."

<em>7.2/48 = x/100</em>

Solve accordingly; cross multiply, 720 = 48x; divide both sides of the equation by 48 to isolate the variable, 720/48 = 48x/48; now you have your final answer which is:

15 = x; going back to the "formula" this means 15% of his money has gone to waste. I hope this helped! :)

5 0

1 year ago

In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a

geniusboy [140]

Answer:

BC:BN=8:3

Step-by-step explanation:

ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.

Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD

But, BC= BN+NC

Therefore, BC:BN=(BN+NC):BN

⇒BC:BN=(3+5):3

⇒BC:BN=8:3

4 0

1 year ago