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Sav [38]
2 years ago
6

Jack and Jim went biking. Jack biked for 5 1/3 hours with average speed 12 1/2 miles per hour. Jim traveled exactly 1 1/5 as far

as Jack did. How long was Jim’s trip?

Mathematics
2 answers:
GuDViN [60]2 years ago
5 0
The relation between distance, velocity and time can be expressed using the following equation:
Distance = velocity * time

We are given that:
Jack biked 5 1/3 hours (time = 5 1/3 hours) with average speed of 12 1/2 miles per hour (velocity = 12 1/2 miles/hour)
Substitute in the above equation to get the distance traveled by Jack as follows:
Distance traveled by Jack = 12 1/2 * 5 1/3 = 66.6667 miles

Now, we know that:
Jim traveled 1 1/5 as far as Jack, this means that:
Distance traveled by Jim = 66.6667 * 1 1/5 = 80 miles
JulijaS [17]2 years ago
5 0
I don't know if you are allowed to use a calculator for these problems, but I did. I am able to multiply the mixed fractions without a calculator if you need help with that please comment below.  Please let me know if you are still confused on how to get the answer! Hope this helped!

My Final Answer: Jim's trip was 146 2/3 miles long.

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