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2 years ago

7

A tin of paint covers a surface area of 50m2. Each tin costs £5.60. The entire surface of a solid cylindrical rod with diameter

8m and height 12m needs to be painted. Find the minimum cost of painting the rod. (NO NEED FOR EXLENATION)

1 answer:

bearhunter [10]2 years ago

5 0

the answer is in the picture

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Farmer Jack needs 1,800 square feet of garden space to have enough corn for a year. His garden space is currently 10 5⁄6 feet by

Alja [10]

5/6 can be simplified to 0.83. 10.83*18=194.94 square feet. 1,800 minus 194.94 is 1605.06 more square feet required

6 0

2 years ago

Find the partial derivatives indicated Assume the variables are restricted to a domain on which the function is defined. z=x8+3y

ahrayia [7]

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the partial derivatives indicated Assume the variables are restricted to a domain on which the function is defined. z= $x^{8}$ + $3^{y}$ + $x^{y}$

a) Zx b) Zy

In differentiation, if y = axⁿ, y' = $nax^{n-1} \ where \ n\ is\ a\ constant$ . Applying this in question;

Given the function z = x⁸+ $3^{y}$ + $x^{y}$

$Z_x = \frac{\delta z}{\delta x} = 8x^{7} + 0 + yx^{y-1} \\\frac{\delta z}{\delta x} = 8x^{7} + yx^{y-1} \\$

Note that y is treated as a constant since we are to differentiate only with respect to x.

For Zy;

$Z_y = \frac{\delta z}{\delta y} =0+ 3^{y} ln3 + x^{y}lnx \\\frac{\delta z}{\delta y} = 3^{y} ln3 + x^{y}lnx } \\$

Here x is treated as a constant and differential of a constant is zero.

6 0

2 years ago

Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th

larisa86 [58]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

$p_v =2*P(z>0.546)=0.585$

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

$\hat p=0.2$ estimated proportion

$p_o=0.16$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>0.546)=0.585$

4 0

2 years ago

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

REY [17]

<span>Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

–5</span>

5 0

2 years ago

Read 2 more answers

contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lots

Tju [1.3M]

The houses can be placed in 362,880 ways.

<u>Step-by-step explanation:</u>

The 9 houses are each in different design.

The each lot can place any of the 9 houses.

The 1st lot can place anyone house of all the 9 houses.
The 2nd lot can place one of remaining 8 houses.
The 3rd lot can place one of remaining 7 houses.

Similarly, the process gets repeated until the last house is placed on a lot.

<u>From the above steps, it can be determined that :</u>

The number of ways to place the 9 houses in 9 lots = 9!

⇒ 9×8×7×6×5×4×3×2×1

⇒ 362880 ways.

Therefore, the houses can be placed in 362880 ways.

5 0

2 years ago