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1 year ago

7

A tin of paint covers a surface area of 50m2. Each tin costs £5.60. The entire surface of a solid cylindrical rod with diameter

8m and height 12m needs to be painted. Find the minimum cost of painting the rod. (NO NEED FOR EXLENATION)

1 answer:

bearhunter [10]1 year ago

5 0

the answer is in the picture

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Ana played 4444 rounds of golf and then played her lowest round of golf with a score of 80808080.

777dan777 [17]

Answer:

I'm going to chose B sorry if that the wrong answer

7 0

1 year ago

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Shelley compared the number of oak trees to the number of maple trees as part of a study about hardwood trees in a woodlot. She

Sedbober [7]

Answer:

72

Step-by-step explanation:

<u>Initial ratio of maple trees to oak trees</u>

9:5

<u>New ratio of maple trees to oak trees</u>

3:11

Number of oak trees = 132

<u>Number of maple trees</u>

132*3/11 = 36

<u>Total number of trees</u>

132+36 = 168

<u>Initial number of maple trees </u>

168*9/14 = 108

<u>The difference in the number of maple trees:</u>

108 - 36 = 72

7 0

1 year ago

Read 2 more answers

A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r

eduard

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

Radius= 1.5 m

Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= $2\pi rh$

Considering, π= 3.14

⇒ lateral surface area of cylinder= $2\times 3.14\times 1.5\times 2.5$

⇒ lateral surface area of cylinder= $23.55 \ m^{2}$

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= $\frac{16500}{23.55} = 700.6369 \approx 701$

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

8 0

2 years ago

What is the pressure difference Δp=pinside−poutside? Use 1.28 kg/m3 for the density of air. Treat the air as an ideal fluid obey

Sidana [21]

This is an incomplete question, here is a complete question.

A hurricane wind blows across a 7.00 m × 12.0 m flat roof at a speed of 150 km/h.

What is the pressure difference Δp = p(inside)-p(outside)? Use 1.28 kg/m³ for the density of air. Treat the air as an ideal fluid obeying Bernoulli's equation.

Answer : The pressure difference will be, $1.11\times 10^3Pa$

Step-by-step explanation :

As we are given:

Speed = 150 km/h = 41.66 m/s

Density = $\rho=1.28kg/m^3$

Area = A = 7.00 m × 12.0 m

Formula used :

$\Delta P=\frac{1}{2}\times \rho \times v^2$

Now put all the given values in this formula, we get:

$\Delta P=\frac{1}{2}\times (1.28kg/m^3)\times (41.66m/s)^2$

$\Delta P=1.11\times 10^3Pa$

Thus, the pressure difference will be, $1.11\times 10^3Pa$

7 0

2 years ago

Lyman Company returned $750 of goods it had purchased from another company. The original invoice was for $4,200, 3/10, n/30. Wha

Scilla [17]

Calculation:
<span>3/10 </span><span><span> 3---------></span>3% discount</span><span><span>
10--------></span>the days in the discount period, the company has 10 days to pay the bill in full.</span>

Therefore

Lyman pays the balance within the discount period

($4,200 – $750) x .03 = $103.50

the discount is <span>$103.50</span>

4 0

1 year ago