1) 26 different outcomes are in the sample space.
2) 1 / 26 is the probability that the computer produces the first letter of your first name.
<u>Step-by-step explanation:</u>
<u>1) You have to find out the different outcomes in the sample space :</u>
- A "Sample space" is defined as the set of all the possible outcomes of an event.
- Here, the given event is randomly selecting a letter from the alphabets.
Therefore, the sample space must contain all the possible alphabets that can be chosen randomly.
The sample space is the set of all the 26 alphabets in English language.
⇒ Sample space = {A,B,C,D...........,Y,Z}
⇒ 26 different outcomes.
<u>2) The probability the computer produces the first letter of your first name :</u>
Here, the required outcome is getting the first letter of your first name.
Probability = No. of required outcomes / total no. of outcomes.
For example, The name Alex Davis has the first letter of the fist name as alphabet 'A'.
∴ Probability = 1 / 26
Similarly, for any first name there is going to be any one alphabet from the 26 alphabets, thus the probability to get the first letter will be always 1 / 26.
The fact that the first chosen student was a girl is already decided, so there is no need to find the probability of that happening. There are a total of 13+10, or 23 students. A girl was already selected, so that leaves 22 students. The chance that a boy is chosen is 10/22, or 5/11.
Answer:
The probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Step-by-step explanation:
According to the given statement we have to make five letter code from A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.
Thus the probability of picking the first letter M = 1/5
After that we require the sequence (not E, not E, not E) which is equal to:
= 3/4 * 2/3* *1/2
= 1/4
Now multiply 1/5 and 1/4
1/5 * 1/4
= 1/20
= 0.05
Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....