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skelet666 [1.2K]
2 years ago
14

a crane cable can support a maximum load of 15,000 kg. if a bucket has a mass of 2,000 kg and gravel has a mass of 1,500 kg for

every cubic meter, how many cubic meters of gravel (g) can be safely lifted by the crane?
Mathematics
2 answers:
Brut [27]2 years ago
7 0
2000 + 1500g ≤ 15000
1500g ≤ 15000 - 2000
1500g ≤ 13000
g ≤ 13000/1500
g ≤ 8 2/3

Therefore, the crane can safely lift a maximum of 8 2/3 cubic meters of gravel.
Novay_Z [31]2 years ago
3 0

Answer:

26/3

Step-by-step explanation:

i just did it

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Stolb23 [73]
2x^2 - 32
2(x^2 - 16)
2(x + 4)(x - 4) <==
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2 years ago
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The cost of 5 gallons of ice cream has a standard deviation of 8 dollars with a mean of 29 dollars during the summer. What is th
Feliz [49]

Answer:

97.74% probability that the sample mean would differ from the true mean by less than 1.9 dollars if a sample of 92 5-gallon pails is randomly selected

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 29, \sigma = 8, n = 92, s = \frac{8}{\sqrt{92}} = 0.8341

What is the probability that the sample mean would differ from the true mean by less than 1.9 dollars if a sample of 92 5-gallon pails is randomly selected?

This is the pvalue of Z when X = 29 + 1.9 = 30.9 subtracted by the pvalue of Z when X = 29 - 1.9 = 27.1. So

X = 30.9

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{30.9 - 29}{0.8341}

Z = 2.28

Z = 2.28 has a pvalue of 0.9887

X = 27.1

Z = \frac{X - \mu}{s}

Z = \frac{27.1 - 29}{0.8341}

Z = -2.28

Z = -2.28 has a pvalue of 0.0113

0.9887 - 0.0113 = 0.9774

97.74% probability that the sample mean would differ from the true mean by less than 1.9 dollars if a sample of 92 5-gallon pails is randomly selected

7 0
2 years ago
One catcher's mitt and 10 outfielder's gloves cost $239.50. How much does each item cost if 1 catcher's mitt and 5 outfielder's gl
seraphim [82]
Make an equation for each statement with x being catcher's mitts and y being outfielder's gloves.

x + 10y = 239.50       and        x + 5y = 134.50

Multiply the second equation through by -1 giving -x - 5y = -134.50

Combine the equations vertically

 x + 10y = 239.50
-x   - 5y = -134.50

giving

5y = 105
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Now substitute for y:
x + 10(21) = 239.50
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Thus, Catchers mitts $29.50 and outfielder's gloves are $21
3 0
2 years ago
a homeowner wants to carpet two rooms that each measure 12 ft by 15 ft. how many square yards of carpet should be ordered
Lelu [443]

3 feet = 1 yard

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7 0
2 years ago
On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches
Gala2k [10]

Answer:

g(x)=6(3)^x

Step-by-step explanation:

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f(x)=6(\frac{1}{3})^x

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It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

(x,y)\rightarrow (-x,y)

Using the rule then we get

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

By using

x^{-a}=\frac{1}{x^a}

Substitute x=-1

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Substitute x=0

g(0)=6

Therefore,g(x)=6(3)^x is true.

8 0
2 years ago
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