James will end up with his original t cars and half of (t+13) cars, so will have ...
... t + (t+13/2) = (3t +13)/2 . . . . cars James has after Paul's gift
Thats good for Alex?
Haha, what is the rest of the question? I am happy to help
Answer:
6xy - 8x + 5y - 4z
Step-by-step explanation:
6xy - 20y + 7z - 8x + 25y - 11z
Group the ones with the variable first to make an equation:
6xy - 8x - 20y + 25y + 7z - 11z
Solve the equation
6xy - 8x +5y - 4z
For a probability distribution the expected value is the summation of product of probabilities with their respective data values. Let x be the probability that Jackson goes gym for 2 days and y be the probability that he goes gym for 3 days.
For the given case we have following values and their probabilities:
0 : 0.1
2 : x
3 : y
So the expected value will be = 0(0.1) + 2(x) + 3(y)
Expected value is given to be 2.05. So we can write the equation as:
2x + 3y = 2.05 (Equation 1)
Also for a probability distribution, the sum of probabilities must always equal to 1. So we can set up the second equation as:
0.1 + x + y = 1
x + y = 0.9 (Equation 2)
From Equation 2 we can write the value of x to be x = 0.9 - y. Using this value in equation 1, we get:
2(0.9 - y) + 3y = 2.05
1.8 - 2y + 3y = 2.05
1.8 + y = 2.05
y = 0.25
Using the value of y in equation 2 we get value of x to be 0.65
Therefore we can conclude that:
The probability that Jackson goes to gym for 2 days is 0.65 and the probability that he goes to gym for 3 days is 0.25
5 hours + 4 hours = 9 hours
30 minutes + 45 minutes =75 minutes
60 minutes in an hour, so 75 minutes =1 hour and 15 minutes, or 1.25 hours
9 hours + 1.25 hours =10.25 hours or 10 hours and 15 minutes.