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Taya2010 [7]
2 years ago
14

Mr. Chang’s class has 28 students, 4/7 of whom are girls. Which equation shows how to determine the number of girls in Mr. Chang

’s class?
A. 28 ÷ 4/7 = 49

B. 28 x 4/7 = 16

C. 4/7 ÷ 28 = 1/49

D. 7/4 ÷ 28 = 1/16
Mathematics
2 answers:
mars1129 [50]2 years ago
6 0

Answer:

b

Step-by-step explanation:

Veronika [31]2 years ago
5 0

First, multiply it with each other and then it is 28 *4/7 = 16

Meaning that there is 16 girls in Mr. Chang's class

Making the answer B. 28 x 4/7 = 16 to be correct

<em>I hope this helps, love!</em>

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1. Which formula defines the sequence f(1)=2, f(2)= 6, f(3)= 10, f(4)= 14, f(5)= 18?
Natasha_Volkova [10]

Answer:

f(n) =4 + f(n-1) \\for\ n>2

Step-by-step explanation:

Given

f(1)=2\\ f(2)= 6\\ f(3)= 10\\ f(4)= 14\\ f(5)= 18

Required

Determine the formula

First, we need to solve common difference (d)

d = f(n) - f(n-1)

Take n as 2

d = f(2) - f(2-1)

d = 6 - 2

d = 4

Represent each function as a sum of the previous

f(1) = 2

f(2) = 2 + 4 = f(1) + 4

f(3) = 6 + 4 = f(2) + 4

f(4) = 10 + 4 = f(3) + 4

f(5) = 14 + 4 = f(4) + 4

Represent the function as f(n)

f(n) =f(n-1) + 4

Reorder

f(n) =4 + f(n-1) \\for\ n>2

7 0
2 years ago
On an algebra test, the highest grade was 42 points higher than the lowest grade. The sum of the two grades was 138. Find the lo
miv72 [106K]


you could use this equation to help you solve it;

x + (x + 42) = 138

the first step is to combine like terms;

2x = 138 -42

2x = 96

X = 96/2

X = 48

we already solved for x now substitute it in the equation I gave you.

48 + (48 + 42) = 138

48 + 90 = 138

hope it helped...if you have any concerns just let me know:) 

3 0
2 years ago
A shoe manufacturer compared material A and material B for the soles of shoes. Twelve volunteers each got two shoes. The left wa
sveta [45]

Answer:

a) Are dependent since we are mesuring at the same individuals but on different times and with a different method

b) If we see the qq plot we don't have any significant deviation for the values and we don't have any heavy tail so we can conclude that we can approximate the differences with the normal distribution.

c) p_v =P(t_{(12)}>0.969) =0.353

So the p value is higher than the significance level given, so then we can conclude that we FAIL to reject the null hypothesis. So we can conclude that the mean differences is NOT significantly different from 0 .

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

The Q-Q plot, or quantile-quantile plot, "is a graphical tool to help us assess if a set of data plausibly came from some theoretical distribution such as a Normal or exponential".

Let put some notation  

x=value for A , y = value for B

A: 379, 378, 328, 372, 325, 304, 356, 309, 354, 318, 355, 392

B: 372, 376, 328, 368, 283, 252, 369, 321, 379, 303, 328, 411

(a) Are the two samples paired or independent? Explain your answer.

Are dependent since we are mesuring at the same individuals but on different times and with a different method

(b) Make a normal QQ plot of the differences within each pair. Is it reasonable to assume a normal population of differences?

The first step is calculate the difference d_i=A_i-B_i and we obtain this:

d: 7,2,0,4,42,52,-13,-12,-25,15,27,-19

In order to do the qqplot we can use the following R code:

d<-c(7,2,0,4,42,52,-13,-12,-25,15,27,-19)

qqnorm(d)

And the graph obtained is attached.

If we see the qq plot we don't have any significant deviation for the values and we don't have any heavy tail so we can conclude that we can approximate the differences with the normal distribution.

(c) Choose a test appropriate for the hypotheses above and justify your choice based on your answers to parts (a) and (b). Perform the test by computing a p-value, make a test decision, and state your conclusion in the context of the problem

The system of hypothesis for this case are:

Null hypothesis: \mu_A- \mu_B = 0

Alternative hypothesis: \mu_A -\mu_B \neq 0

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{80}{12}=6.67

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =23.849

The 4 step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{6.67 -0}{\frac{23.849}{\sqrt{12}}}=0.969

The next step is calculate the degrees of freedom given by:

df=n-1=12-1=11

Now we can calculate the p value, since we have a two tailed test the p value is given by:

p_v =P(t_{(12)}>0.969) =0.353

So the p value is higher than the significance level given, so then we can conclude that we FAIL to reject the null hypothesis. So we can conclude that the mean differences is NOT significantly different from 0 .

4 0
2 years ago
your friend deposits $9500 in an investment account that earns 2.1% annual interest. what is the balance after 11 years when the
solmaris [256]

Answer:

The answer is "$ 11,961.43"

Step-by-step explanation:

Given values:

P =  $ 9500

r= 2.1 %

time (t)= 11 year

total quarterly year =4

Formula:

A= P (1+\frac{r}{n})^{nt}\\\\

quarterly time = 4 \times 11

                         = 44

A= P (1+\frac{r}{n})^{nt}\\\\

A = 9500 ( 1+ \frac{0.021}{4})^{44}\\\\A = 9500(\frac{4+ 0.021}{4} )^{44} \\\\A = 9500(\frac{4.021}{4} )^{44} \\\\A= 9500 (1.00525)^{44}\\\\A= 9500(1.25909819)\\\\A= 11,961. 43\\

8 0
1 year ago
Here is a scale drawing of a window frame that uses a scale of 1 cm to 6 inches.Create another scale drawing of the window frame
Tresset [83]

Answer:

Step-by-step explanation:

Below is the rectangle in the attachment.

Current scale:

1 cm : 6 inches

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Using the scale:

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Using the scale:

Length = a × 12 inches

Width = b × 12 inches

Note that there is an enlargement of the rectangle to form the new rectangle. The length and width of new rectangle drawn will be 2 × the length and width of the rectangle seen below.

8 0
2 years ago
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