At a large high school 40 percent of the students walk to school, 32 percent of the students have been late to school at least o
1 answer:
Answer:
Option b
Step-by-step explanation:
Given that at a large high school 40 percent of the students walk to school, 32 percent of the students have been late to school at least once, and 37.5 percent of the students who walk to school have been late to school at least once.
Proportions of Students coming late to school = coming by walk and late to school + coming by other means and late to school = 0.32 (given)
Proportions of students coming late atleast once and by walk
= 40% * 375%
=
the probability that the student selected will be one who both walks to school and has been late to school at least once
=0.15
(option b)
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Answer:
A. Because the measure of the angle is
and the angles
and
are Vertical angles. Therefore, they are congruent (
)
B.
Step-by-step explanation:
<h3> <em><u>The missing figure is attached.</u></em></h3><h3 /> You can observe in the figure that the parallel lines and
are intersected by a another line
(this is a transversal).
Let's begin with PART B:
Observe that the angles and
are located inside the parallel lines and they alternate sides of the transversal. Therefore, we can determine that these angles are "Alternate Interior Angles".
Since the lines and
are parallel, we know that the Alternate Interior Angles are congruent. Then:
Now we can solve the PART A.
Observe the figure.
Since the angle and the angle
share the same vertex, they are "Vertical angles" and, therefore, they are congruent:
Answer:
First person: $107
Second person: $98
Third person: $93
Step-by-step explanation:
Let be "f" the amount of money (in dollars) that the first person contributed to the purchase, "s" the amount of money (in dollars) that the second person contributed to the purchase and "t" the amount of money (in dollars) that the third person contributed to the purchase.
With the information given in the exercise, you can set up the following equations:
Equation 1 →
Equation 2 →
Equation 3 →
Substitute the Equations 2 and 3 into the Equation 1 and then solve for "f":
Finally, substitute the value of "f" into the Equation 2 and then into the Equation 3, in order to find the values of "s" and "t".
Therefore, you get: