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DENIUS [597]
1 year ago
14

At a large high school 40 percent of the students walk to school, 32 percent of the students have been late to school at least o

nce, and 37.5 percent of the students who walk to school have been late to school at least once. One student from the school will be selected at random. What is the probability that the student selected will be one who both walks to school and has been late to school at least once?
a. 0.12
b. 0.15
c. 0.1875
d. 0.345
e. 0.72
Mathematics
1 answer:
tatyana61 [14]1 year ago
7 0

Answer:

Option b

Step-by-step explanation:

Given that at  a large high school 40 percent of the students walk to school, 32 percent of the students have been late to school at least once, and 37.5 percent of the students who walk to school have been late to school at least once.

Proportions of Students coming late to school = coming by walk and late to school + coming by other means and late to school = 0.32 (given)

Proportions of students coming late atleast once and by walk

= 40% * 375%

= 0.4(0.375)\\=0.15

the probability that the student selected will be one who both walks to school and has been late to school at least once

=0.15

(option b)

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A factory produces 1,250,000 toys each year. The number of toys is expected to increase by about 150% per year. Which model can
kozerog [31]

Answer: Our required model is n=1250000(1.15)^t

Step-by-step explanation:

Since we have given that

Number of toys = 1,250,00

Every year is expected to increase by about 150% pr year.

So, initial value = 1250,000

Rate of change = 150%

Let the number of time = t years.

So, we will use "Compound interest":

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Hence, our required model is n=1250000(1.15)^t

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1 year ago
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TU = 3, RS = 15, TW = 4, TR = 9; Assume that the sides of triangle TUW are proportional to the sides of triangle TRS. What is th
VMariaS [17]

Answer:

  WS=8\ units

Step-by-step explanation:

we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal and the corresponding angles are also equal

In this problem

\frac{TU}{TR}=\frac{UW}{RS}=\frac{TW}{TS}

we have

TU=3\ units, RS=15\ units, TW=4\ units,TR=9\ units

Find the value of TS

\frac{TU}{TR}=\frac{TW}{TS}

substitute

\frac{3}{9}=\frac{4}{TS}

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1 year ago
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The distribution of heights of a certain breed of terrier has a mean of 72 centimeters and a standard de- viation of 10 centimet
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Answer:

Pr(X-Y ≤ 44.2) = 0.5593

Step-by-step explanation:

for a certain breed of terrier

Mean(μ) = 72cm

Standard deviation (σ) = 10cm

n = 64

For a certain breed of poodle

Mean(μ) = 28cm

Standard deviation (σ) = 5cm

n = 100

Let X be the random variable for the height of a certain breed of terrier

Let Y be the random variable for the height of a certain breed of poodle

μx - μy = 72 -28

= 44

σx - σy = √(σx^2/nx + σy^2/ny)

= √10^2/64 + 5^2/100

= √100/64 + 25/100

= √ 1.8125

= 1.346

Using normal distribution,

Z= (X-Y- μx-y) / σx-y

Z= (44.2 - 44) / 1.346

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Z= 0.1486

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Pr(Z ≤ 44.2) = 0.5 + 0.0593

= 0.5593

Therefore,

Pr(X-Y ≤ 44.2) = 0.5593

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