<u>Complete Question</u>
The circle is inscribed in triangle PRT. A circle is inscribed in triangle P R T. Points Q, S, and U of the circle are on the sides of the triangle. Point Q is on side P R, point S is on side R T, and point U is on side P T. The length of R S is 5, the length of P U is 8, and the length of U T is 6. Which statements about the figure are true?
Answer:
(B)TU ≅ TS
(D)The length of line segment PR is 13 units.
Step-by-step explanation:
The diagram of the question is drawn for more understanding,
The theorem applied to this problem is that of tangents. All tangents drawn to a circle from the same point are equal.
Therefore:
|PQ|=|PU|=8 Units
|ST|=|UT| =6 Units
|RS|=|RQ|=5 Units
(b)From the above, TU ≅ TS
(d)Line Segment |PR|=|PQ|+|QR|=8+5=`13 Units
Answer:
The area of new pumpkin patch is
= 15 x² + 380 x + 2400
Step-by-step explanation:
Given as :
The length of rectangular patch = L = 40 meters
The width of rectangular patch = W = 60 meters
So, The area of rectangular patch = Length × Width
Or,
= L × W
So ,
= 40 meters × 60 meters
Or,
= 2400 meters²
Again The Width of new Patch = ( 40 + 3 x ) meter
And The Length of new Patch = ( 60 + 5 x ) meter
Or,
= L × W
So ,
= ( 40 + 3 x ) meters × ( 60 + 5 x ) meters
Or,
= 2400 + 200 x + 180 x + 15 x²
Or,
= 15 x² + 380 x + 2400
Hence The area of new pumpkin patch is
= 15 x² + 380 x + 2400 Answer
Answer:
b. not at all
Step-by-step explanation:
• a line goes on forevee in every direction
• a ray continues forever in one direction only
• a segment has a set length and will not extend
Answer:
the speed btn sonya and issac would make a right angled trangle hence easy 2 solve through pythogoras

then find the
![\sqrt[?]{?}](https://tex.z-dn.net/?f=%20%5Csqrt%5B%3F%5D%7B%3F%7D%20)
hence get 45
since it was 12 mins we need 2 multiply by 12
hence

Therefore it's 540mph