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2 years ago

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A projectile is fired directly upward. The compound inequality 89 – 9.8t < 10.6 or 89 – 9.8t > 20.4 represents a projectil

e’s velocity that is less than 10.6 m/s or greater than 20.4 m/s. Solve the compound inequality. The solution to the inequality 89 – 9.8t < 10.6 is ? . The solution to the inequality 89 – 9.8t > 20.4 is? . To determine when the projectile hits the ground, solve 89 – 9.8t = 0 for t. Rounding to the nearest whole second, t is about ? seconds. The viable solution set is ?

2 answers:

Tom [10]2 years ago

7 0

Given compound inequality 89 – 9.8t < 10.6 or 89 – 9.8t > 20.4.

Let us solve them one by one.

89 – 9.8t < 10.6

Subtracting 89 from both sides, we get

89-89 – 9.8t < 10.6 - 89

-9.8t < -78.4

Dividing both sides by -9.8, we get

t > 8.

<em>Note: Inequality sign get flip on dividing both side by a negative number.</em>

89 – 9.8t > 20.4

Subtracting 89 from both sides, we get

89-89 – 9.8t < 20.4 - 89

-9.8 t < - 68.6.

Dividing both sides by -9.8, we get

t < 7

<em>Note: Inequality sign get flip on dividing both side by a negative number.</em>

<h3><em> The solution to the inequality 89 – 9.8t < 10.6 is </em>t > 8. </h3><h3> The solution to the inequality 89 – 9.8t > 20.4 is t < 7.</h3>

When the projectile hits the ground:

89 – 9.8t = 0

Subtracting 89 from both sides, we get

89 - 89 – 9.8t = 0 -89.

-9.8t = -89.

Dividing both sides by 9.8, we get

<h3>to the nearest whole second t is about 9 seconds.</h3><h3>Therefore, variable solution set is {t < 7, t > 8, t = 9}.</h3><h3 />

Nady [450]2 years ago

3 0

Answer:

The solution to the inequality 89 – 9.8t < 10.6 is ?

t > 8

The solution to the inequality 89 – 9.8t > 20.4 is?

t < 7

To determine when the projectile hits the ground, solve 89 – 9.8t = 0 for t.

t = 9.08163265306

Rounding to the nearest whole second, t is about ?

9 seconds.

The viable solution set is ?

[0, 7) or (8, 9]

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Answer:

Sadie's error is " she made error in step 2 $=\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}$ where $a\geqslant 0$ "

Because she made error in splitting the powers to simplify the square root

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Step-by-step explanation:

Given that " Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, "

It can be written as $\sqrt{54a^7b^3}$ where $a\geqslant 0$

The given expression is $\sqrt{54a^7b^3}$ where $a\geqslant 0$

To find Sadie's error and explain the correct answer :

Sadie's steps are

$\sqrt{54a^7b^3}$ where $a\geqslant 0$

$=\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}$

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$\sqrt{54a^7b^3}$ where $a≥0$

$=\sqrt{(9\times 6)(a^{6+1})(b^{2+1})$

$=\sqrt{(3^2\times 6)(a^6.a^1)(b^2.b^1)$ (by using the identity $a^{m+n}=a^m.a^n$

$=\sqrt{3^2\times 6\times ((a^3)^2.a)(b^2.b)$ (by using the identity $a^{mn}=(a^m)^n$ )

$=3ab\sqrt{6ab}$

Therefore $\sqrt{54a^7b^3}=3ab\sqrt{6ab}$ where $a\geqslant 0$

<h3>The correct answer is $3ab\sqrt{6ab}$ where $a\geqslant 0$ </h3>

Sadie's error is " she made error in step 2 $=\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}$ " where $a\geqslant 0$

Because she made error in splitting the powers to simplify the square root

<h3>Therefore the correct answer for Sadie's expression is $3ab\sqrt{6ab}$ where $a\geqslant 0$ </h3>

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Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

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(a) The desired margin of error is $0.10.

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$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

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(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

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Rounding up, 97

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