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Semenov [28]
2 years ago
11

The equation 3w + 4j = 39 is used to determine the number of water bottles w and the number of juice bottles j that can be bough

t for $39. If you purchase 6 bottles of juice, how many bottles of water can you buy?
Mathematics
2 answers:
zlopas [31]2 years ago
6 0

Answer:

5

Step-by-step explanation:

The number of water bottles = w

The number of juice bottles = j

We have, 3w + 4j = 39

When we purchase 6 bottles of juice, j = 6

So,

3w + 4j = 39

3w + 4 \times 6 = 39

3w + 24 = 39

3w = 39 - 24

3w = 15

w = \frac{15}{3}

w = 5

Therefore, we can buy 5 bottles of water.

jarptica [38.1K]2 years ago
3 0

Juice bottles are J, replace j with 6 in the equation and solve for w:

3w + 4(6) = 39

3w + 24 =39

Subtract 24 from both sides:

3w = 15

Divide both sides by 3:

w = 15/3

w = 5

You can buy 5 water bottles.

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For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

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Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

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Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



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