Answer: This coil will not be enough to complete the job.
Step-by-step explanation:
The circumference of the coil of wiring can be calculated with:
Where r is the radius and 
The radius can be calculated by dividing the diameter by 2. Then:
Convert 9 inches to yards (1 yard=36 inches):
Substitute this radius into the formula:
Since there are 21 circles of wire, you need to multiply 
by 21:
The coil has 32.97 yards of wire and Alex needs 34 yards, therefore, this coil will not be enough to complete the job.
Answer: $1,540
Step-by-step explanation:
Given the following amount charged by a worker :
First 45 hours = $14 per hour
time and half for the next 10 hours
Double time for all hours after that:
If he worked for 80 hours :
First 45 hours = (45 × $14) = $630
Next 10 hours:
Time and half for 10 hours is equivalent to (10 × 1.5) = 15 hours
(15 × $14) = $210
Double time for all subsequent hours :
80 - (45 + 10) = 80 - 55 = 25
Double time : (2 × 25) = 50 hours
(50 × 14) = $700
Hence, total amount earned :
($630 + $210 + $700)
= $1,540
You can round 976 to 1000 and 522 to 500. So it would be
1000 - 500 = 500. The answer you would get after subtracting 976-522 would be more than 400 if you round it.
To solve this problem you must follow the proccedure shown below:
1. Amount of lemonade in pints:
1 <span>quart of water=2 pints
1 pint of lemon
(9 ounces of honey)(0.0625 pints/1 ounce)=0.56 pints
Total in pints=2 pints+1 pint+0.56 pints
Total in pints=3.56 pints
2. </span>Amount of lemonade in<span> cups:
Total in cups=(3.56 pints)(2 cups/1 pint)
Total in cups=7.12 cups
3. </span>Amount of lemonade in<span> ounces:
Total in ounces=(7.12 cups)(8 ounces/1 cup)
Total in ounces=56.96 ounces</span>
Answer:
Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.
Step-by-step explanation:
Consider the provided information.
The mean number (per group) who recognize the Yummy brand name is 12.5, and the standard deviation is 0.58.
Mean = μ= 12.5
σ = 0.58
n = 15
![\mu\pm2\sigma=12.5\pm 2(0.58)\\\mu\pm2\sigma=12.5\pm1.16\\\mu\pm2\sigma=[11.34, 13.66]](https://tex.z-dn.net/?f=%5Cmu%5Cpm2%5Csigma%3D12.5%5Cpm%202%280.58%29%5C%5C%5Cmu%5Cpm2%5Csigma%3D12.5%5Cpm1.16%5C%5C%5Cmu%5Cpm2%5Csigma%3D%5B11.34%2C%2013.66%5D)
Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.
