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kotegsom [21]
2 years ago
6

PLEASE HELP! I SUCK AT MATHHH, THANK YOUUU!!!

Mathematics
1 answer:
vfiekz [6]2 years ago
3 0

Answer: 21/400

Step-by-step explanation:

Multivitamin:

8 cherry, 5 grape, and 7 orange

Total fruits in Multivitamin container :

(8 + 5 + 7) = 20

P(orange) = Total required outcome / Total possible outcomes)

P(orange) = 7/20

Calcium vitamin :

11 berry, 3 lemon, and 6 pineapple

Total fruits in calcium vitamin container:

(11 + 3 + 6) = 20

Probability of picking a lemon:

P(lemon) = Total required outcome / Total possible outcomes)

P(lemon) = 3/20

Therefore, probability of picking an orange and a lemon equals:

P(orange) × p(lemon) = (7/20) × (3/20) = 21/400

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Lawrence's parents pay him a base allowance of $20 per week and $3.55 per hour for extra chores he completes. Write an equation
natali 33 [55]
The answer would be 20w+3.55h=T
7 0
2 years ago
A gardener wants to run a border around the outside of her garden. She plots it on a grid to plan how much she will need. The ga
levacccp [35]
Distance between (2, 5) and (8, 5) = 8 - 2 = 6
Distance between (8, 5) and (8, 3) = 5 - 3 = 2
Distance between (8, 3) and (2, 3) = 8 - 2 = 6
Distance between (2, 3) and (2, 5) = 5 - 3= 2

Total length of border = 6 + 2 + 6 + 2 = 16


5 0
2 years ago
A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.
BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to 160\ ft^{2}

Part b) The volume is equal to 240\ ft^{3}

Part c) The volume water left in the trough will be 84\ ft^{3}

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

so

<em>Find the area of two rectangles</em>

A=2[12*5]=120\ ft^{2}

<em>Find the area of two trapezoids</em>

A=2[\frac{1}{2}(8+2)h]

Applying Pythagoras theorem calculate the height h

h^{2}=5^{2}-3^{2}

h^{2}=16

h=4\ ft

substitute the value of h to find the area

A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}

The exterior surface area is equal to

120\ ft^{2}+40\ ft^{2}=160\ ft^{2}

Part b) Find the volume

We know that

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=20\ ft^{2}

L=12\ ft

substitute

V=20(12)=240\ ft^{3}

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

A=\frac{1}{2}(5+2)(2)=7\ ft^{2}

<em>step 2</em>

Find the volume

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=7\ ft^{2}

L=12\ ft

substitute

V=7(12)=84\ ft^{3}

4 0
2 years ago
What is the value of y?<br> y = <br><br> Find the following angle measures.<br> mJKM = °<br> mMKL
shusha [124]

Answer: ∠JKM = 106\textdegree and

 ∠JKM = 74\textdegree

Step-by-step explanation:

Since we have given that

∠JKM=10y+6

∠MKL=8y-6

Since they are linear pairs ,

So, 10y+6+8y-6=180\textdegree \\\\18y=180\textdegree \\\\y=\frac{180\textdegree}{18\textdegree}\\\\y=10\textdegree

∠JKM = 10\times 10+6=100+6=106\textdegree

and

∠MKL = 8\times 10-6=80-6=74\textdegree

8 0
2 years ago
Read 2 more answers
Study the steps used to solve the equation. Given: StartFraction c Over 2 EndFraction minus 5 equals 7 Step 1: StartFraction c O
Bas_tet [7]

Answer:

  1. addition property of equality
  2. integers are closed to addition
  3. identity element
  4. multiplication property of equality
  5. commutative property of multiplication; reals are closed to multiplication; identity element

Step-by-step explanation:

<u>Given</u>:

  c/2 -5 = 7

  Step 1: c/2 -5 +5 = 7 +5

  Step 2: c/2 +0 = 12

  Step 3: c/2 = 12

  Step 4: 2(c/2) = 12(2)

  Step 5: c = 24

<u>Find</u>:

  The property that justifies each step of the solution.

<u>Solution</u>:

  Step 1: addition property of equality (lets you add the same to both sides)

  Step 2: integers are closed to addition

  Step 3: identity property of addition (adding 0 changes nothing)

  Step 4: multiplication property of equality

  Step 5: closure of real numbers to multiplication; identity property of multiplication

_____

It is hard to say what "property" you want to claim when you simplify an arithmetic expression. Above, we have used the property that the sets of integers and real numbers are closed to addition and multiplication. That is, adding or multiplying real numbers gives a real number.

In Step 5, we can rearrange 2(c/2) to c(2/2) using the commutative property of multiplication. 2/2=1, and c×1 = c. The latter is due to the identity element for multiplication: multiplying by 1 changes nothing.

Apart from the arithmetic, the other properties used are properties of equality.  Those let you perform any operation on an equation, as long as you do it to both sides of the equation. The operations we have performed in this fashion are adding 5 and multiplying by 2.

8 0
2 years ago
Read 2 more answers
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