Distance between (2, 5) and (8, 5) = 8 - 2 = 6
Distance between (8, 5) and (8, 3) = 5 - 3 = 2
Distance between (8, 3) and (2, 3) = 8 - 2 = 6
Distance between (2, 3) and (2, 5) = 5 - 3= 2
Total length of border = 6 + 2 + 6 + 2 = 16
Answer:
Part a) The exterior surface area is equal to 
Part b) The volume is equal to 
Part c) The volume water left in the trough will be 
Step-by-step explanation:
Part a) we know that
The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles
so
<em>Find the area of two rectangles</em>
![A=2[12*5]=120\ ft^{2}](https://tex.z-dn.net/?f=A%3D2%5B12%2A5%5D%3D120%5C%20ft%5E%7B2%7D)
<em>Find the area of two trapezoids</em>
![A=2[\frac{1}{2}(8+2)h]](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%288%2B2%29h%5D)
Applying Pythagoras theorem calculate the height h



substitute the value of h to find the area
![A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%288%2B2%29%284%29%5D%3D40%5C%20ft%5E%7B2%7D)
The exterior surface area is equal to

Part b) Find the volume
We know that
The volume is equal to

where
B is the area of the trapezoidal face
L is the length of the trough
we have


substitute

Part c)
<em>step 1</em>
Calculate the area of the trapezoid for h=2 ft (the half)
the length of the midsegment of the trapezoid is (8+2)/2=5 ft

<em>step 2</em>
Find the volume
The volume is equal to

where
B is the area of the trapezoidal face
L is the length of the trough
we have


substitute

Answer: ∠JKM =
and
∠JKM = 
Step-by-step explanation:
Since we have given that
∠JKM=10y+6
∠MKL=8y-6
Since they are linear pairs ,
So, 
∠JKM = 
and
∠MKL = 
Answer:
- addition property of equality
- integers are closed to addition
- identity element
- multiplication property of equality
- commutative property of multiplication; reals are closed to multiplication; identity element
Step-by-step explanation:
<u>Given</u>:
c/2 -5 = 7
Step 1: c/2 -5 +5 = 7 +5
Step 2: c/2 +0 = 12
Step 3: c/2 = 12
Step 4: 2(c/2) = 12(2)
Step 5: c = 24
<u>Find</u>:
The property that justifies each step of the solution.
<u>Solution</u>:
Step 1: addition property of equality (lets you add the same to both sides)
Step 2: integers are closed to addition
Step 3: identity property of addition (adding 0 changes nothing)
Step 4: multiplication property of equality
Step 5: closure of real numbers to multiplication; identity property of multiplication
_____
It is hard to say what "property" you want to claim when you simplify an arithmetic expression. Above, we have used the property that the sets of integers and real numbers are closed to addition and multiplication. That is, adding or multiplying real numbers gives a real number.
In Step 5, we can rearrange 2(c/2) to c(2/2) using the commutative property of multiplication. 2/2=1, and c×1 = c. The latter is due to the identity element for multiplication: multiplying by 1 changes nothing.
Apart from the arithmetic, the other properties used are properties of equality. Those let you perform any operation on an equation, as long as you do it to both sides of the equation. The operations we have performed in this fashion are adding 5 and multiplying by 2.