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LekaFEV [45]
2 years ago
7

A drawer contains black socks and white socks. 40% of the socks are black socks. A number generator simulates randomly selecting

10 socks from the drawer. The number generator is used 10 times and the number of black socks in each trial is shown in the dot plot.
Which description is correct about the number generator being fair or not?




The number generator is not fair. It picked black socks half of the time.

The number generator is not fair. In three experiments, it picked black socks 50% of the time.

The number generator is fair. It picked the approximate percentage of black socks most of the time.

The number generator is fair. It picked black socks half of the time.

Mathematics
1 answer:
TiliK225 [7]2 years ago
4 0

Answer: The number generator is fair. It picked the approximate percentage of black socks most of the time.

Step-by-step explanation:

A dot plot is a display of dots which represents graphically a data.

Given data of a drawer contains black socks and white socks which 40% are black socks.A number generator simulates randomly selecting 10 socks from the drawer.

The display is representing  the number of black socks in each trial of 10 times.

We can see for most of the trial there is no dot ;that is no black socks.

Only in 2nd to 5th trial black socks picked in approximated percentage of 40%.

⇒The number generator is fair. It picked the approximate percentage of black socks most of the time.

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Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4
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<u>Given:</u>

The given equation is \log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)

We need to determine the extraneous solution of the equation.

<u>Solving the equation:</u>

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule \log _{c}(a)+\log _{c}(b)=\log _{c}(a b), we get;

\log _{4}(x(x-3))=\log _{4}(-7 x+21)

Again applying the log rule, if \log _{b}(f(x))=\log _{b}(g(x)) then f(x)=g(x)

Thus, we have;

x(x-3)=-7 x+21

Simplifying the equation, we get;

       x^2-3x=-7 x+21

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x^2+4x-21=0

Factoring the equation, we get;

(x-3)(x+7)=0

Thus, the solutions are x=3, x=-7

<u>Extraneous solutions:</u>

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)

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Since, we know that \log _{a}(0) is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)

    \log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)

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Simplifying, we get;

Undefined = \log _{4}(70)

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Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

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