The first term is x^4.
The second term is 8x^3
Maximum weight the bridge can support in kilograms is 101696
Step-by-step explanation:
- Step 1: Given capacity of bridge = 100 British tons. Find how many kilograms are equivalent to 1 British ton.
1 British ton = 2240 pounds
1 pound = 0.454 kg
⇒ 1 British ton = 2240 × 0.454 kg = 1016.96 kg
- Step 2: Find how many kilograms are in 100 British tons.
⇒ 100 × 1016.96 = 101696
Answer: $2193
Step-by-step explanation:
v(x) = 32,500
Plug two and three in for x
v(2) = 32,500
v(2) = 32,500(.8464)
v(2) = 27,500
v(3) = 32,500
v(3) = 32,500(.778688)
v(3) = 25,307.36
Subtract v(3) from v(2)
27,500 - 25,307.36 = 2192.64
Round to the nearest dollar to get $2193
Answer:
4.8
Step-by-step explanation:
Let's see here we know the last one can't be the highest because there is no digit that is to the left of the decimal place, so that is a pure fraction, now we're all left with 4 in the left place, so we compare all the digits, and we find that the third option has 8 tenths, which is in fact greater than 8 hundredths or 8 thousandths.
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Average rate of change = [H(100) - H(80)] / (100 - 80)
H(100) = 0.003(100)^2 + 0.07(100) - 0.027 = 0.003(10000) + 0.07(100) - 0.027 = 30 + 7 - 0.027 = 36.973
H(80) = 0.003(80)^2 + 0.07(80) - 0.027 = 0.003(6400) + 0.07(80) - 0.027 = 19.2 + 5.6 - 0.027 = 24.773
Average rate of change = (36.973 - 24.773)/(100 - 80) = 12.2/20 = 0.61
Answer: B