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Ratling [72]
1 year ago
15

​z+w−3 ​6z−10w ​​ ​=k ​=8 ​​ consider the system of equations above, where kkk is a constant. for which value of kkk are there i

nfinitely many (w, z)(w,z)left parenthesis, w, comma, z, right parenthesis solutions?
Mathematics
1 answer:
Reptile [31]1 year ago
8 0
Our system is the following :
z+w-3=k\\
6z-10w=k,\\\text{Solve the first equation for z like this:} \\z=k-w+3\\\text{Substitute in the second equation like this:}\\6(k-w+3)-10w=k\\6k-16w+18=k\\16w=6k+18-k\\w=\frac{1}{16}(6k+18-k)

As you see, the system has only one solution whenever the value of k is. Unlike you have not well written the system. 
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Janice works at a cell phone company. She wants to make a presentation to her team about the features of a new phone. She makes
Advocard [28]
If 1 inch represents 0.5 centimeter, then 28 inches will represent 28 * 0.5 = 14 centimeters and 15 inches will represent 15 * 0.5 = 7.5 centimeters.

The actual dimensions of the phone is: the length is 14 centimeters and the width is 7.5 centimeters.
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1 year ago
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Jillian is selling boxes of cookies to raise money for her basketball team. the 10 oz. box costs $3.50, while the 16 oz. box cos
zhannawk [14.2K]
X + y = 24...y = 24 - x
3.50x + 5.00y = 97.50

3.50x + 5(24 - x) = 97.50
3.50x + 120 - 5x = 97.50
3.50x - 5x = 97.50 - 120
-1.5x = -22.50
x = -22.50/-1.5
x = 15....there were 15 ten oz boxes (x) sold
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2 years ago
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Help me with this question please!
BigorU [14]

Answer:

c = 40d+20

Step-by-step explanation:

He has to pay 20 dollars and that can't multiply so the forty has to multiply and it would have to be by d because c is the total cost

6 0
1 year ago
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Given that tangent theta = negative 1, what is the value of secant theta, for StartFraction 3 pi Over 2 EndFraction less-than th
Rashid [163]

Answer:

sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}

Step-by-step explanation:

Start by noticing that the angle \theta is on the 4th quadrant (between \frac{3\pi}{2} and 2\pi. Recall then that in this quadrant the functions tangent and cosine are positive, while the function sine is negative in value. This is important to remember given the fact that tangent of an angle is defined as the quotient of the sine function at that angle divided by the cosine of the same angle:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Now, let's use the information that the tangent of the angle in question equals "-1", and understand what that angle could be:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-1=\frac{sin(\theta)}{cos(\theta)}\\-cos(\theta)=sin(\theta)

The particular special angle that satisfies this (the magnitude of sine and cosine the same) in the 4th quadrant, is the angle \frac{7\pi}{4}

which renders for the cosine function the value \frac{\sqrt{2} }{2}.

Now, since we are asked to find the value of the secant of this angle, we need to remember the expression for the secant function in terms of other trig functions: sec(\theta)=\frac{1}{cos(\theta)}

Therefore the value of the secant of this angle would be the reciprocal of the cosine of the angle, that is: sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}

6 0
1 year ago
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Ben swims​ 50,000 yards per week in his practices. Given this amount of​ training, he will swim the​ 100-yard butterfly in 51.5
Elanso [62]

Answer:

MArginal productivity: \frac{dt}{dL}=-0.0002

We can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.

Step-by-step explanation:

The marginal productivy is the instant rate of change in the result for an increase in one unit of a factor.

In this case, the productivity is the time he last in the 100-yard. The factor is the amount of yards he train per week.

The marginal productivity can be expressed as:

\frac{dt}{dL}

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We can not derive the function because it is not defined, but we can approximate with the last two points given:

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Then we can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.

This is an approximation that is valid in the interval of 60,000 to  70,000 yards of training.

6 0
1 year ago
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