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1 year ago

What is the reciprocal of 5 5/11

2 answers:

7 0

Multiply 5x11, and add it to 5/11, to turn the number into a single fraction; 60/11. The reciprocal is this number flipped upside down, so the solution is 11/60.

Therefore the solution is 11/60.

Allushta [10]1 year ago

3 0

To find the reciprocal of a fraction you'd switch the numerator with the denominator but since this is a mixed number, multiply the whole number by the denominator then add the numerator and you get a improper fraction and if you get that to find the reciprocal of it, switch the numerator with the denominator(ex. 3 4/5= 3X5=15, 15+4=19, 19/5, reciprocal: 5/19)

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A rectangle is 4 cm longer than it is wide, and its area is 117 cm2 . find its dimensions.

Brilliant_brown [7]

The area of a rectangle is equal L x W

4 cm longer than it is wide L = 4 + W

L x W = 117 we replace L here

(4 + W ) x W = 117

4W + W ^2 = 117

4W + W ^2 -117 = 0
W ^2 +4 W -117 = 0

W² + 4W - 117 = 0


THEN u want to use the use the quadratic formula

OR Factoring gives us

(W + 13)(W - 9) = 0

W = -13 or 9

But it can't be negative, so

W = 9 and L= 9+4 = 13

3 0

2 years ago

Read 2 more answers

Miguel ran for 850 meters and then walked for 2.75 kilometers.

olga55 [171]

Answer:

1900 meters

Step-by-step explanation:

He ran for 850 meters

Walked for 2.75 kilometers, and that's 2.75 * 1000 meters, which is 2750 meters

The total he walked more than he ran is 2750 - 850 = 1900 meters

4 0

2 years ago

A person places $934 in an investment account earning an annual rate of 6.1%, compounded continuously. Using the formula V = P n

mixer [17]

Yes man yes we are here for dinner last night

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2 years ago

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The grocery store sells kumquats for $5.00 a pound and Asian pears for $3.25 a pound. Write an equation in standard form for the

aniked [119]

Okay so your equation is going to be : 18= 5k + 3.25p

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2 years ago

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A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot

Damm [24]

Answer:

a) $p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) $\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

$p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

$\hat p$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545$

$0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591$

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.

5 0

2 years ago