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2 years ago

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A ramp with a constant incline is made to connect a driveway to a front door. At a point 4 feet from the driveway, the height of

the ramp is 12 inches. At a point 6 feet from the driveway, the height of the ramp is 18 inches. What is the rate of change of the ramp’s incline?

1 answer:

katen-ka-za [31]2 years ago

7 0

So, we're finding ratios first okay, for every 4ft:12in and 6ft:18in so for every one foot there is 3 inches which is your rate of incline 1:3 or every one foot there are 3 inches of incline hope this helped you have an amazing day

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Alexandra's bank statement shows a closing balance of $130.68. There are no outstanding checks or deposits. Her checkbook shows

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She has a difference of $2.75, she may have subtracted something wrong while balancing out the check book.

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2 years ago

Read 2 more answers

1. Mac is about to sue his contractor who promised to install a water tank that holds 1880 gallons of water. Mac knows that 1880

zzz [600]

Answer:

option C.

Yes, the water tank is about 245 cubic feet too small

Step-by-step explanation:

step 1

Determine the volume of the cylindrical tank

we know that

The volume of a cylinder is equal to

$V=\pi r^{2} h$

Remember that

$1\ ft=12\ in$

we have

$r=6\ ft\\h=2\ ft\ 2\ in=2+(2/12)=\frac{13}{6}\ ft$

assume

$\pi =3.14$

substitute

$V=(3.14)(6)^{2}(\frac{13}{6})$

$V=244.92\ ft^3$

Compare with 251 cubic feet

$244.92\ ft^3 < 251\ ft^3$

therefore

Yes, the water tank is about 245 cubic feet too small

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2 years ago

Can you simplify before multiplying 14×25/27

castortr0y [4]

Answer:

No.

Step-by-step explanation:

You can not simplify this expression before multiplying it, because no whole numbers go into both 14 and 27, and also no whole numbers go into both, 25 and 27. This is the correct answer to this question.

Hope this helps!!!

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1 year ago

a ball is thrown with a slingshot at a velocity of 110ft/sec at an angle of 20 degrees above the ground from a height of 4.5 ft.

satela [25.4K]

Answer:

$t=2.47\ s$

Step-by-step explanation:

The equation that models the height of the ball in feet as a function of time is

$h(t) = h_0 + s_0t -16t ^ 2$

Where $h_0$ is the initial height, $s_0$ is the initial velocity and t is the time in seconds.

We know that the initial height is:

$h_0 = 4.5\ ft$

The initial speed is:

$s_0 = 110sin(20\°)\\\\s_0 = 37.62\ ft/s$

So the equation is:

$h (t) = 4.5 + 37.62t -16t ^ 2$

The ball hits the ground when when $h(t) = 0$

So

$4.5 + 37.62t -16t ^ 2 = 0$

We use the quadratic formula to solve the equation for t

For a quadratic equation of the form

$at^2 +bt + c$

The quadratic formula is:

$t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}$

In this case

$a= -16\\\\b=37.62\\\\c=4.5$

Therefore

$t=\frac{-37.62\±\sqrt{(37.62)^2 -4(-16)(4.5)}}{2(-16)}$

$t_1=-0.114\ s\\\\t_2=2.47\ s$

We take the positive solution.

Finally the ball takes 2.47 seconds to touch the ground

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2 years ago

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Answer:A. on edge

Step-by-step explanation:

Just took the quiz.

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1 year ago