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Tanzania [10]
2 years ago
15

A ramp with a constant incline is made to connect a driveway to a front door. At a point 4 feet from the driveway, the height of

the ramp is 12 inches. At a point 6 feet from the driveway, the height of the ramp is 18 inches. What is the rate of change of the ramp’s incline?
Mathematics
1 answer:
katen-ka-za [31]2 years ago
7 0
So, we're finding ratios first okay, for every 4ft:12in and 6ft:18in so for every one foot there is 3 inches which is your rate of incline 1:3 or every one foot  there are 3 inches of incline hope this helped you have an amazing day

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The function D(t) defines a traveler's distance from home, in miles, as a function of time, in hours. D(t) = StartLayout enlarge
nalin [4]

- At 2 hours, the traveler is 725 miles from home.

- At 3 hours, the distance is constant, at 880 miles. --> TRUE.

- The total distance from home after 6 hours is 1,062.5 miles --> TRUE.

Step-by-step explanation:

The function D(t) is defined as follows:

D(t) = 300t+125 for t< 2.5

D(t) = 880 for 2.5 \leq 3.5

D(t) = 75t+612.5 for t\leq 6

Where

t is the time in hours

D(t) is the distance covered, in miles, after t hours

Now let's analyze the different statements:

- The starting distance, at 0 hours, is 300 miles. --> FALSE. In fact, if we substitute t = 0 into the 1st equation, we get

D(0) = (300)(0)+125 = 125

So, the distance at t = 0 is 125 miles.

- At 2 hours, the traveler is 725 miles from home. --> TRUE. In fact, if we substitute t = 2 into the 1st equation,

D(2) = (300)(2)+125 = 725

- At 2.5 hours, the traveler is 875 miles from home. --> FALSE. In fact, for t=2.5 we have to use the 2nd equation, which states that the distance is:

D(t) = 880

So, not 875 miles.

- At 3 hours, the distance is constant, at 880 miles. --> TRUE. This is clearly visible from the 2nd equation: for t between 2.5 and 3.5 (so, in this case), the distance is

D(t) = 880

- The total distance from home after 6 hours is 1,062.5 miles --> TRUE. In fact, if we replace t = 6 into the last equation,

D(6)) = 75(6)+612.5=1062.5

Learn more about functions:

brainly.com/question/3511750

brainly.com/question/8243712

brainly.com/question/8307968

Learn more about  distance:

brainly.com/question/3969582

#LearnwithBrainly

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1 year ago
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Which graph should Laila choose? Explain your reasoning by completing the sentence. Click arrows to choose an answer from each m
Leno4ka [110]

Answer:

box plot

Step-by-step explanation:

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For the upcoming holiday season, Dorothy wants to mold 20 bars of chocolate into tiny pyramids. Each bar of chocolate contains 6
lorasvet [3.4K]

Answer:

A. 180

Step-by-step explanation:

20*6=120\ in^{3}\ of\ chocolate \\\\\frac{1*1*2}{3} =\frac{2}{3}\ in^{3}\ per\ pyramid\\\\\frac{120}{\frac{2}{3} }\ cubes\\\\\frac{120*3}{2}\ cubes\\\\\frac{360}{2}\ cubes\\\\180\ cubes

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Which statement is true regarding the graphed functions?
anyanavicka [17]

Answer:

the last option: f(-2)=g(-2)

Step-by-step explanation:

Make sure you have the numerical answer for each of the functional expressions that are shown among the possible solution choices:

f(4) = -14  (what the blue function reads  [its y-value] when x is 4)

g(4) = 10  (what the red function reads [its y-value] for x=4)

g(-2) = 4 (y-value of the red function when x is -2)

f(2) = -8 (y-value of the blue function for x = 2)

f(-2) = 4 (y-value of the blue function for x =-2)

use them to compare the options they give you, and the only one that matches is the last option.

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What is the following quotient? sqrt 6 + sqrt 11 / sqrt 5 +sqrt 3
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Answer:

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

Step-by-step explanation:

Let's translate what you've written in words to an expression with mathematical symbols.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}}

To solve this, you need to multiply both the numerator and denominator with the conjugate of the denominator.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

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