Write an inequality to compare the integers -5 and -6

Which polynomial correctly combines the like terms and expresses the given polynomial in standard form?

STatiana [176]

Answer:

D. $3x^4 + x^3y - 8x^2y^2 + 9xy^3 - 13y^4$

Step-by-step explanation:

$9xy^3 - 4y^4 - 10x^2y^2 + x^3y + 3x^4 + 2x^2y^2 - 9y^4 =$

$= 9xy^3 - 13y^4 - 8x^2y^2 + x^3y + 3x^4$

$= 3x^4 + x^3y - 8x^2y^2 + 9xy^3 - 13y^4$

4 0

1 year ago

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Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of

nikklg [1K]

Answer:

a. 5 + 2i, 13 + 2i, 29 + 2i

Step-by-step explanation:

We'll use the formula f(z) = 2z + (3 - 2i) for each iteration. The output of the first iteration will be come the input of the second iteration, and so on.

So, we start with z0 = 1 + 2i and we plug that into the base equation:

z0 = 1 + 2i ==> f(z) = 2(1 + 2i) + 3 - 2i = 2 + 4i + 3 - 2i = 5 + 2i

z1 = 5 + 2i ==> f(z) = 2(5 + 2i) + 3 - 2i = 10 + 4i + 3 - 2i = 13 + 2i

z2 = 13 + 2i ==> f(z) = 2(13 + 2i) + 3 - 2i = 26 + 4i + 3 - 2i = 29 + 2i

z3 = 29 + 2i

8 0

1 year ago

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The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

Leona [35]

Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

5 0

2 years ago

PLEASE HELPPPP , WILL GIVE BRAINLIESTTTTT

insens350 [35]

Answer:

80%

Step-by-step explanation:

What I did was just play with the numbers. But first, you'd multiply 6.00 time 3 because it's for the three people. Then just multiply 18 with .8 and bingo! The answer you get is 14.40, so the discount would be 80%

Hope this helps!

5 0

1 year ago

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An employment agency requires applicants average at least 70% on a battery of four job skills tests. If an applicant scored 70%,

brilliants [131]

Answer:

atleast 52

Step-by-step explanation:

Given that an employment agency requires applicants average at least 70% on a battery of four job skills tests.

An applicant scored 70%, 77%, and 81% on the first three exams,

Since weightages are not given we can assume all exams have equal weights