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2 years ago

How many units of a 10% solution are needed to prepare 500 units of a 2% solution?

1 answer:

8 0

First find how many units of solution there is:

500* 2% = 500(.02) = 10 units

You need 10 units of solution in 'x' units of a 10% solution.

x*10% = 0.1x = 10 units -----> x = 10/0.1 = 100

100 units are needed

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Supervisor: "Last week, you spoke with 800 customers in 40 hours."

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Answer:12

Step-by-step explanation:

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2 years ago

Becky is buying fabric to make new pillows for her couch. She spends $71.50 on striped fabric and $52.25 on checkered fabric. If

Gnom [1K]

Answer:

i think you add both fabric prices then divide with 5.50

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2 years ago

Segment YB is x+3 units long and segment BW is 2x-9 units long. The diagonal YW is ___ units long.

Gnom [1K]

Answer:

3x - 6

Step-by-step explanation:

Segment YB = x + 3

Segment BW = 2x - 9

Add the two segments.

x + 3 + 2x - 9

3x - 6

The diagonal YW is 3x - 6 units long.

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1 year ago

Read 2 more answers

Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi

Romashka [77]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84

P(not winning for 6 days) = 0.84⁶

P(not winning for 6 days) = 0.3513

Finally,

P(at least 1 win) = 1 - P(not winning for 6 days)

P(at least 1 win) = 1 - 0.3513

P(at least 1 win) = 0.6487

6 0

2 years ago

Greenfields is a mail order seed and plant business. The size of orders is uniformly distributed over the interval from $25 to $

LekaFEV [45]

Answer:

a) 47.55

b) 58

c) 47.88

Step-by-step explanation:

Given that the size of the orders is uniformly distributed over the interval

$25 ( a ) to $80 ( b )

a) Determine the value for the first order size generated based on 0.41

parameter for normal distribution is given as ; a = 25, b = 80

size/value of order = a + random number ( b - a )

= 25 + 0.41 ( 80 - 25 )

= 47.55

b) Value of the last order generated based on random number (0.6)

= a + random number ( b - a )

= 25 + 0.6 ( 80 - 25 )

= 25 + 33 = 58

c) Average order size

= ∑ order 1 + order 2 + ----- + order 10 ) / 10

= (47.55 + ...... + 58 ) / 10

= 478.8 / 10 = 47.88

4 0

2 years ago