Answer:
p-value (0.0208) is less than alpha = 0.05 reject H0.
Step-by-step explanation:
we have the following data:
sample size = n = 75
x, the number to evaluate is 45
the sample proportion would be: x / n = 45/75
p * = 0.6
Now, the null and alternative hypotheses are:
H0: P = 0.72
Ha: P no 72
two tailed test
statistic tes = z = (p * - p) / [(p * (1-p) / n)] ^ (1/2)
replacing we have:
z = (0.6 - 0.72) / [(0.72 * (1-0.72) / 75)] ^ (1/2)
z = -2.31
p-vaule = 2 * p (z <-2.31)
using z table, we get:
p-vaule = 2 * (0.0104)
p-vaule = 0.0208
Therefore, p-value (0.0208) is less than alpha = 0.05 reject H0.
Answer:
The expression used to represent g(x) as inverse of f(x) is 
Option B is correct.
Step-by-step explanation:
We are given:
We need to find the expression that could be used to verify g(x) is the inverse of f(x).
We know that 
is inverse of function
So placing value of f(x) in g(x)
So, the expression used to represent g(x) as inverse of f(x) is
Option B is correct.
We can also solve to prove that
kaaaaaaaaaaaaaaaaabbbichaStep-by-step explanation:
1 g = 1 cm^3 = 1 mL. Hence, 2000 g = 2000 cm^3 = 2000 mL.
The percent to 300 out of 12 is 144
