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FrozenT [24]
2 years ago
13

Ann is grouping 38 rocks. She can put them into groups of 10 rocks or as single rocks. What are the different ways Ann can group

the rocks?
Mathematics
1 answer:
hoa [83]2 years ago
7 0

Answer: There will be two different ways of doing so.

Step-by-step explanation:

Since we have given that

Total number of rocks =38

If we want to groups of 10 rocks or as single rocks then there are 2 different ways ;

<u>Case I:</u>

if we group into 10 rocks

there will be four sets in which Ist set contains 10 rocks

Second set contains 10 rocks

Third set contains 10 rocks

and Fourth set remains with 8 rocks only.

<u>Case II:</u>

if we group as single rocks .

There will be 38 sets .



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A ball is thrown down from a balcony with a vertical velocity (in ft/s) given by
fenix001 [56]

Answer:

–90 < –32t – 10 < –58

Step-by-step explanation:

We want the velocity to be BETWEEN -90 and -58.

Whenever we need a quantity, let it be A, to be between two numbers, p and q (p is less than q), we can write it as:

p < A < q

Similarly, here we need the velocity, -32t-10 to be BETWEEN -90 and - 58 (with -90 being the smaller number). Thus we can write:

–90 < –32t – 10 < –58

This is the correct choice, 2nd choice.

4 0
2 years ago
Read 2 more answers
Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes
valentinak56 [21]

Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

x-3x=-14-2

-2x=-16

2x = 16

dividing by 2 on both sides, we will get,

x =\frac{16}{2}

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>

The line segment \overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}

\overrightarrow{PA}=x+2+3x-14

=4x-12

=4(8)-12 ( since x=8)

=32-12

=20

<h3>∴ \overrightarrow{PA}=20 units</h3>
3 0
2 years ago
Your promotional budget for the year is $300 for personal selling, $300 for sales promotion, \$1,500 for advertising, and $500 f
aleksandr82 [10.1K]

Answer:

to get the total promotion budget for the year we will add $300 for personal selling plus $300 for sales promotion plus $1500 for advertising plus $500 for image promotion to the a total of 2600 dollars

8 0
2 years ago
At what points does the helix r(t) = sin t, cos t, t intersect the sphere x2 + y2 + z2 = 65? (round your answers to three decima
Firdavs [7]
\mathbf r(t)=\langle x(t),y(t),z(t)\rangle=\langle\sin t,\cos t,t\rangle

x^2+y^2+z^2=\sin^2t+\cos^2t+t^2=65
\implies t^2=64
\implies t=\pm8
7 0
1 year ago
Your cell phone plan charges a base charge each month plus a charge per daytime minute of usage and December used 510 daytime mi
algol13

Answer:

In February, 423 daytime minutes is used

Step-by-step explanation:

Let the base plan charges be x

And cost per daytime minute be y

In December,

x  + 510y =  92.25------------------(1)

In January,

x + 397y = 77.56---------------------(2)

Subtracting eq(2) from eq(1)

x  + 510y =  92.25

x + 397y = 77.56

-------------------------------

0  + 113y = 14.69

-------------------------------

y = \frac{14.69}{113}

y =  0.13----------------------------------(3)

Substituting (3) in (1)

x  + 510(0.13) =  92.25

x + 66.3 = 92.25

x = 92.25 - 66.3

x = 25.95

So In February

base plan  + (daytime minute)(cost per daytime minute) = 80.9

25.95 + (daytime minute)(0.13) = 80.9

(daytime minute)(0.13) = 80.9 - 25.95

(daytime minute)(0.13) = 54.95

(daytime minute) =\frac{54.95}{0.13}

daytime minutes = 422.69

daytime minute  \approx 423

3 0
2 years ago
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