<span>As restaurant owner
The probability of hiring Jun is 0.7 => p(J)
The probability of hiring Deron is 0.4 => p(D)
The probability of hiring at least one of you is 0.9 => p(J or D)
We have a probability equation:
p(J or D) = p(J) + p(D) - p(J and D) => 0.9 = 0.7 + 0.4 - p(J and D)
p(J and D) = 1.1 - 0.9 = 0.2
So the probability that both Jun and Deron get hired is 0.2.</span>
Most likely, polygon <span>ABCD</span> has sides of known lengths.
It is also likely that one of the sides of polygon <span>EFGH</span> (not <span>EH</span>) is also known. For instance, its side <span>EF</span>.
If the above is true, we can find the scaling factor as a ratio between lengths of corresponding sides:
<span>r=<span><span>EF</span><span>AB</span></span></span>
Since this ratio is constant for any two corresponding lengths,
<span>r=<span><span>EH</span><span>AD</span></span></span>
From the last two equations we can derive:
<span>EH=AD⋅<span><span>EF</span><span>AB</span></span></span>
Hope That Helped : ) (Took a minute)
<span>The number of dollars collected can be modelled by both a linear model and an exponential model.
To calculate the number of dollars to be calculated on the 6th day based on a linear model, we recall that the formula for the equation of a line is given by (y - y1) / (x - x1) = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (3, 8)
The equation of the line representing the model = (y - 2) / (x - 1) = (8 - 2) / (3 - 1) = 6 / 2 = 3
y - 2 = 3(x - 1) = 3x - 3
y = 3x - 3 + 2 = 3x - 1
Therefore, the amount of dollars to be collected on the 6th day based on the linear model is given by y = 3(6) - 1 = 18 - 1 = $17
To calculate the number of dollars to be calculated on the 6th day based on an exponential model, we recall that the formula for exponential growth is given by y = ar^(x-1), where y is the number of dollars collected and x represent each collection day and a is the amount collected on the first day = $2.
8 = 2r^(3 - 1) = 2r^2
r^2 = 8/2 = 4
r = sqrt(4) = 2
Therefore, the amount of dollars to be collected on the 6th day based on the exponential model is given by y = 2(2)^(5 - 1) = 2(2)^4 = 2(16) = $32</span>
32x+64 = 160
32x = 96
x = 3
