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2 years ago

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Ann is grouping 38 rocks. She can put them into groups of 10 rocks or as single rocks. What are the different ways Ann can group

the rocks?

1 answer:

hoa [83]2 years ago

7 0

Answer: There will be two different ways of doing so.

Step-by-step explanation:

Since we have given that

Total number of rocks =38

If we want to groups of 10 rocks or as single rocks then there are 2 different ways ;

<u>Case I:</u>

if we group into 10 rocks

there will be four sets in which Ist set contains 10 rocks

Second set contains 10 rocks

Third set contains 10 rocks

and Fourth set remains with 8 rocks only.

<u>Case II:</u>

if we group as single rocks .

There will be 38 sets .

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The angle Johnny holds his pen on paper creates a linear pair. The measure of one angle is 13x+7. The measure of the second angl

lisov135 [29]

we know that

Angles in a linear pair are supplementary angles

So

Let

A-------> the first angle

B------> the second angle

$A+B=180\\$ ----> equation $1$

$A=13x+7\\ B=2A-1=B=26x+13$

Substitute the values of A and B in the equation $1$

$13x+7+26x+13=180\\ 39x=180-20\\ x=\frac{160}{39}$

$\frac{160}{39}=4.10\ degrees$

therefore

the answer is

the value of x is $4.10\ degrees$

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2 years ago

Read 2 more answers

What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve.

zvonat [6]

Answer:

$x=-2.38$

$x=-4.62$

Step-by-step explanation:

The question is $(2x+3)^2+8(2x+3)+11=0$

<em>We let $u=2x+3$ , so the equation becomes:</em>

$u^2+8u+11=0$

Where $a=1, b=8, c=11$

Putting it in the quadratic formula, we have:

<u>Quadratic formula:</u> $\frac{-b+-\sqrt{b^2-4ac} }{2a}$

Substituting we have: $\frac{-8+-\sqrt{(8)^2-4(1)(11)} }{2(1)}\\=\frac{-8+-\sqrt{20} }{2}\\=\frac{-8+-2\sqrt{5} }{2}\\=-4+\sqrt{5}, -4-\sqrt{5} }$

<em>We let $u=2x+3$ , so x is:</em>

<em> $u=2x+3\\(-4+\sqrt{5})=2x+3\\x=\frac{-7+\sqrt{5}}{2}=-2.38$ </em>

<em>and</em>

<em> $u=2x+3\\(-4-\sqrt{5})=2x+3\\x=\frac{-7-\sqrt{5}}{2}=-4.62$ </em>

The solutions of the equation is $x=-2.38$ (rounded to 2 decimal places), and $x=-4.62$ (rounded to 2 decimal places)

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2 years ago

Find the x-intercept for 11x - 33y = 99

photoshop1234 [79]

The answer is twelve and you can thank me later

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2 years ago

In a random sample of 130 students, only 7 had been placed in the wrong math class. What is the best point estimate for the prop

Ivenika [448]

We have the given in the problem as mentioned:
A total of 130 students and only 7 had been placed in the wrong math class.
With this given, we can easily draw the proportion of all students who have been placed in the wrong math class by estimation method and the solution is shown below:

Proportion = 7/130

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2 years ago

Sara has 20 sweets.

nalin [4]

Answer:

The probability that the two sweet will not be same type is $\frac{111}{190}$

Step-by-step explanation:

P(two sweets not same) = 1 - P( two sweets will be same)

There are 3 possible outcomes where two sweets will be same.

1. it can be two liquor-ice, 2. it can be 2 mint and 3. it can be two humbug

P(two liquor-ice) $=\frac{12}{20} \times\frac{11}{19}= \frac{33}{95}$

P(two mint) $=\frac{5}{20} \times \frac{4}{19} =\frac{1}{19}$

P(tow humbug) $=\frac{3}{20} \times\frac{2}{19} =\frac{3}{190}$

Now we have:

P(two sweets not same) = 1 - P( two sweets will be same)

$=1- \left(\frac{33}{95}+ \frac{1}{19}+ \frac{3}{190} \right)$

$1-\frac{79}{190}$

$=\frac{111}{190}$

Therefore, the probability that the two sweet will not be same type is $\frac{111}{190}$

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2 years ago