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madreJ [45]
2 years ago
14

Which of the following are exterior angles? Check all that apply.

Mathematics
2 answers:
choli [55]2 years ago
8 0

Answer:

<h3>A. C. E. F.</h3><h3>That is, 2, 3, 5 and 6.</h3>

Step-by-step explanation:

In geometry, <em>exterior angles are any angle place between any side of a shape and a line extended from the next side</em>, as the figure shows.

As you can see, angle 2 and 3 are formed by a side of the triangle and an extended line from the next side. Similarly, angles 5 and 6 are formed the same way. Therefore, those four  are exterior angles.

Ludmilka [50]2 years ago
7 0

5. 6. and 2. answers apex.



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a recipe calls for 3 ounces of flour for every 2 ounces of sugar. Find the constant of proportionality.
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3:2 


for every 3 ounces of flour, you need 2 ounces of sugar
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2 years ago
Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a differen
Anna007 [38]

Answer:

5 miles.

Step-by-step explanation:

Consider the question: Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a different route taking 2 1/2 hours. How many miles did Jinghua hike on the return trip ?

First of all, we will find Jinghua's speed using given information as:

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Convert mixed fractions into improper fractions:

4\frac{1}{2}\Rightarrow \frac{9}{2}

2\frac{1}{4}\Rightarrow \frac{9}{4}

\text{Jinghua's speed}=\frac{\frac{9}{2}\text{ Miles}}{\frac{9}{4}\text{ Hours}}

Using property \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}:

\text{Jinghua's speed}=\frac{9*4\text{ Miles}}{9*2\text{ Hours}}

\text{Jinghua's speed}=\frac{2\text{ Miles}}{\text{ Hour}}

We know that distance is equal to the product of speed and time.

\text{Distance}=\text{Speed}\times\text{Time}

Since we have been given that Jingua hiked the return trip at the same average rate, so distance covered by her on return trip would be speed (2 miles her hour) times given time (2 1/2 hours).

\text{Distance covered by Jingua on return trip}=\frac{2\text{ Miles}}{\text{ Hour}}\times 2\frac{1}{2}\text{ Hours}

\text{Distance covered by Jingua on return trip}=2\text{ Miles}\times \frac{5}{2}

\text{Distance covered by Jingua on return trip}=5\text{ Miles}

Therefore, Jingua hiked 5 miles on her return trip.

8 0
2 years ago
Ethan bought 4 packages of pencils. After he gave 8 pencils to his friends, he had 40 pencils left over. How many pencils were i
swat32

Answer:

12 pencils in each package.

Step-by-step explanation:

Given:

Ethan bought 4 packages of pencils.

No of Packages = 4

No of pencils given to friend = 8 pencils

No of pencils left over =40 pencils

∴Total Number of Pencils = No of pencils given to friend + No of pencils left over =40+8 =48

Total Number of pencils in each package = \frac{\textrm{Total Number of Pencils}}{\textrm{No Of Packages}}= \frac{48}{4}= 12 \ pencils

8 0
2 years ago
The line segments of a cube include edges, the diagonals of the faces, and the diagonals through the interior of the cube. Which
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They diagonal through the interior of the cube is the longest. The hypotenuse is the longest side of a right triangle. The diagonal of the cube is the hypotenuse of a right angle with legs that are diagonal of a face and an edge. The edges are the shortest. They are legs of a right triangle with the diagonal of a face as the hypotenuse.


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2 years ago
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Archimedes (ca. 287-212 B.C.) was able to use clever geometric means to determine the relative volumes of a cylinder and the con
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Answer:

The ration of the volume of  cone to that of   cylinder is   \frac{V_{cone}}{V_{cy}} = \frac{1}{3}  

Step-by-step explanation:

From the question we are told that

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The volume of a cylinder is mathematically represented as

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Now the ratio we are to obtain is

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                   \frac{V_{cone}}{V_{cy}} = \frac{\frac{1}{3} }{1}         Note: this is possible because the height and base

                   \frac{V_{cone}}{V_{cy}} = \frac{1}{3}        radius  are the same

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2 years ago
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