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yawa3891 [41]
2 years ago
6

I NEED HELP PLS ANSWER

Mathematics
1 answer:
Yakvenalex [24]2 years ago
4 0

Answer:

B. Inscribed equilateral triangle.

Step-by-step explanation:

An equilateral triangle is a type of triangle that has all sides to have the same length.

An inscribed figure or shape is one which has been constructed within the boundaries of another figure or shape.

In the given question, the markings is construction of an inscribed equilateral triangle. This procedure of the construction after completion, generate the triangle as shown in the construction attached to this answer.

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The number of people being served went from 6 to 24, so the serving quadrupled.
So multiply 2.5 by 4 and you get 10 pounds of apples.
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2 years ago
If a set xy-axes has 20 grid units in each direction and the greatest value of the data to be placed on the horizontal axis is 1
Alborosie
Use 7 scale point.
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1 year ago
R(-9, 4) and S(2,-1); Find T.
madreJ [45]

Answer:

12.083 units

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where

(x_1,y_1) = (-9,4)

(x_2,y_2) = (2,-1)

Replacing these values in the distance formula

D =\sqrt{(-9-2))^2+(4-(-1))^2}

D =\sqrt{(-11)^2+(5)^2}

D =\sqrt{121+25}

D =\sqrt{146}

D= 12.083

Hence the distance is 12.083 units

3 0
2 years ago
Eric is studying people's typing habits. He surveyed 525 people and asked whether they leave one space or two spaces after a per
hichkok12 [17]

Answer:

The confidence interval is (0.81, 0.87).

Step-by-step explanation:

There's 90% confidence that population proportion is within the interval obtained from the following formula:

\hat{p}\pm z_{\alpha/2}\sqrt{\frac{\hat{p}*(1-\hat{p})}{n}}

Knowing that the sample size, n=525 we obtain the proportion of people from the sample who leave one space after a period as \hat{p}=\frac{440}{525}=0.8381\approx 0.84.

We then look for the critical value:

z_{\alpha/2}=1.645

Now we can replace in the formula to obtain the confidence interval:

0.84\pm 1.645\sqrt{\frac{0.84*(1-0.84)}{525}}= (0.8137; 0.8663)

Therefore we can say that there's 90% probability that the population proportion of people who leave one space after a period lies between the values (0.8137; 0.8663).

3 0
2 years ago
Read 2 more answers
Abraham throws a ball from a point 40 m above the ground. The height of the ball from the ground level after ‘t' seconds is defi
Minchanka [31]

Answer:

8.899s

Solve: -5t^+40t+40

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