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2 years ago

I NEED HELP PLS ANSWER

Mathematics

1 answer:

Yakvenalex [24]2 years ago

4 0

Answer:

B. Inscribed equilateral triangle.

Step-by-step explanation:

An equilateral triangle is a type of triangle that has all sides to have the same length.

An inscribed figure or shape is one which has been constructed within the boundaries of another figure or shape.

In the given question, the markings is construction of an inscribed equilateral triangle. This procedure of the construction after completion, generate the triangle as shown in the construction attached to this answer.

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Which point is a solution of x + 2y ≤ 4?

SVEN [57.7K]

(1,1) because x + 2y <4
=1 + 2(1)
= 3 which is less than 4

4 0

2 years ago

Read 2 more answers

Jada created the two-way table below to describe the performance of her basketball team this season.

kramer

To answer the question, all the statements must be analyzed with the data presented in the table.
From the table we get that the team played 16 games at home and 11 games away from home.
In total, they played 27 games.
Of the 16 games at home, the team won 6. Then, the proportion of games won at home is:
6/16 = 0.375.
Of the 11 games away from home, the team won 3. Then the proportion of games won away from home is:
3/11 = 0.272.
0.375 is not twice 0.272.
Then the first statement is incorrect.

The ratio of games won at home is 6/16 = 3/8. Therefore, the second statement is incorrect. The team does not win 3/5 of the games at home.
The total number of games won is 9 and the total number of games is 27.
So, the third statement is incorrect. The team does not win half of the games.
The fourth statement is true. The team played 27 games

The fifth statement is false because the team won more than 6 games. They won 3 games away from home and 6 games at home

Finally, the sixth statement is correct, because the team lost 10 games at home and 8 away from home. However, the PERCENTAGE of games lost away from home is greater than the PERCENTAGE of games lost at home. Therefore, it is more likely that the team loses when playing away from home.

3 0

2 years ago

Read 2 more answers

Tickets to a musical cost $30 for adults and $12 for children. At one particular performance 960 people attended and $19 080 was

postnew [5]

In order to solve this, you have to set up a systems of linear equations.

Let's say that children = c and adults = a

30a + 12c = 19,080
a + c = 960

I'm going to show you how to solve this system of linear equations by substitution, the easiest way to solve in my opinion.

a + c = 960
- c - c
---------------------- ⇒ Step 1: Solve for either a or c in either equation.
a = 960 - c

20(960 - c)+ 12c = 19,080
19,200 - 20c + 12c = 19,080
19,200 - 8c = 19,080
- 19,200 - 19,200
---------------------------------- ⇒ Step 2: Substitute in the value you got for a or c
8c = -120 into the opposite equation.
------ ---------
8 8

c = -15

30a + 12(-15) = 19,080
30a - 180 = 19,080
+ 180 + 180
-------------------------------
30a = 19,260
------- -----------
30 30

a = 642
__________________________________________________________

I just realized that there can't be a negative amount of children, so I'm sorry if these results are all wrong.

7 0

2 years ago

Read 2 more answers

Use the graph to write an explicit function to represent the data and determine how much money Amy earned in week 5.

zalisa [80]

Answer:

3rd option

$f(n)=5(3)^{n-1}$

$f(5)=405$

Step-by-step explanation:

So we are given the following points:

(1,5)

(2,15)

(3,45)

(4,135)

This is a geometric sequence because there is a common ratio, 3. That is you can keep multiply 3 to a previous y-coordinate to get the next y-coordinate.

The formula for a geometric sequence is $f(n)=a_1 \cdot r^{n-1}$

where $a_1$ is the first term and r is the common ration.

So we have

$f(n)=5 \cdot (3)^{n-1}$ .

If you want to know the fifth term, just plug in 5:

$f(5)=5 \cdot (3)^{5-1}$

Simplifying:

$f(5)=5 \cdot 3^4$

$f(5)=5 \cdot 81$

$f(5)=405$

3 0

2 years ago

Read 2 more answers

among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play

kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0

2 years ago