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forsale [732]
2 years ago
10

The projected number of employed writers and authors in 2016 is 153,000. 12.4% of those will have some college experience but no

degree, and 84.1% will have a bachelor's degree or higher. If this holds true, how many more writers and authors with bachelor's degree will there be than those with only some college experience and no degree? a. 147,645 b. 109,701 c. 134,028 d. 128,673 Please select the best answer from the choices provided A B C D
Mathematics
1 answer:
Airida [17]2 years ago
6 0

Answer:

B. 109,701

Step-by-step explanation:

Number of employed writers and authors = 153,000

Number of employed writers and authors with college experience but no degree =0.124\cdot 153,000=18,972 (12.4%)

Number of employed writers and authors with a bachelor's degree or higher =0.841\cdot 153,000=128,673 (84.1%)

Difference =128,673-18,972=109,701

Hence, there are 109,701 more writers and authors with bachelor's degree than those with only some college experience and no degree.

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Lemur [1.5K]

Answer:

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Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

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Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

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Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

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