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forsale [732]
2 years ago
10

The projected number of employed writers and authors in 2016 is 153,000. 12.4% of those will have some college experience but no

degree, and 84.1% will have a bachelor's degree or higher. If this holds true, how many more writers and authors with bachelor's degree will there be than those with only some college experience and no degree? a. 147,645 b. 109,701 c. 134,028 d. 128,673 Please select the best answer from the choices provided A B C D
Mathematics
1 answer:
Airida [17]2 years ago
6 0

Answer:

B. 109,701

Step-by-step explanation:

Number of employed writers and authors = 153,000

Number of employed writers and authors with college experience but no degree =0.124\cdot 153,000=18,972 (12.4%)

Number of employed writers and authors with a bachelor's degree or higher =0.841\cdot 153,000=128,673 (84.1%)

Difference =128,673-18,972=109,701

Hence, there are 109,701 more writers and authors with bachelor's degree than those with only some college experience and no degree.

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A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an adult is
MakcuM [25]

Answer:

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 5 minutes

Sample mean, \bar{x} = 4.61 minutes

Sample size, n = 15

Alpha, α = 0.05  

Sample standard deviation, s = 0.75 minutes

a) First, we design the null and the alternate hypothesis  

H_{0}: \mu = 5\text{ minutes}\\H_A: \mu \neq 5\text{ minutes}  

We use two-tailed t test to perform this hypothesis.  

b) Formula:  

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have  

t_{stat} = \displaystyle\frac{4.61 - 5}{\frac{0.75}{\sqrt{15}} } = -2.0139  

c) Now, we calculate the p-value using the standard table.

P-value = 0.0638

d) Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Option a) Fail to reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05.

4 0
2 years ago
Zac and Lynn are each traveling on a trip. So far, Zac has traveled 123.75 miles in 2.25 hours. Lynn leaves half an hour after Z
Savatey [412]

Complete question is;

Zac and Lynn are each traveling on a trip. So far, Zac has traveled 123.75 miles in 2.25 hours. Lynn leaves half an hour after Zac. So far

she has traveled 105 miles in 1.75 hours. Assume Zac and Lynn travel at constant rates.

Let a represent the number of hours that have elapsed since Zac started traveling. Let y represent the number of miles traveled. Write a system of linear equations that represents the distance each of them has traveled since Zac left on his trip.

Assume Zac and Lynn continue to travel at the same constant rates and make no stops.

Determine the solution of the system of linear equations.

Answer:

Zac: y = 55a

Lynn: y = 60(a - ½)

6 hours after Zac started traveling, both Zac and Lynn would have covered 330 miles each.

Step-by-step explanation:

Zac has traveled 123.75 miles in 2.25 hours. Since he travels at constant speed, we can say;

zac's speed = 123.75/2.25 = 55 mi/hr

Similarly, Lynn traveled 105 miles in 1.75 hours. Thus, since she travels at a constant speed;

Lynn's speed = 105/1.75 = 60 mi/hr

Now, we are told that a represents the number of hours that have elapsed since Zac started traveling and y represents the number of miles traveled.

Thus;

a hours after Zac started travelling, his distance covered will be;

Zac: y = 55a

Now,for Lynn, since she started ½ an hour after Zac, it means a hours after Zac started, she had traveled (a - ½) hours.

Thus, Lynn's distance traveled after Zac started = 60(a - ½)

Lynn: y = 60(a - ½)

The solution will be when they have travelled equal distances a hours after Zac started. Thus;

55a = 60(a - ½)

55a = 60a - 30

60a - 55a = 30

5a = 30

a = 30/5

a = 6 hours

Putting 6 for a in y = 55a, we have;

y = 55 × 6

y = 330 miles

5 0
2 years ago
A graphic designer wants to translate rectangle DEFG using T–1, 2(x, y). The pre-image has coordinates D(–1, 3),
Lesechka [4]

Answer:The answer is B !

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
After four years of college, Erica has to start paying off all her student loans. Her first payment is due at the end of this mo
tatiyna

Answer:

Therefore, the approximate monthly payment is $548.85

Step-by-step explanation:

The amount of student loans Erica currently has = $34,006.00

The duration over which Erica is to pay back the loan = 7 years

The annual interest rate for the loan = 9.1%

Therefore, we have the geometric sequence formula is given as follows;

A_n = P( 1 + r)^n - M \times \left [ \dfrac{(1 + r)^n-1}{r} \right ]

Where;

M = The monthly payment

P = The initial loan balance = $34,006.00

r = The annual interest rate = 9.1%

n = The number of monthly payment = 7 × 12 = 84

Aₙ = The amount remaining= 0 at the end of the given time for payment

Substituting the values into the above formula, , we get;

0 = 34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} - M \times \left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]

M = \dfrac{34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84}  }{\left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]} \approx 548.85

Therefore, the approximate monthly payment = $548.85

6 0
2 years ago
A room with a length of 270 cm and width 150 cm is to be covered with square tiles .What is the largest size of tiles to be used
Damm [24]

Find the greatest common factor of both numbers:

Factors for 150:

150: 1, 2, 5 , 6, 10, 15, 25, 30, 50, 75, 150

Factors for 270:

1, 2, 3, 5, 6 , 9, 10, 15, 18, 27, 30, 45, 54, 90, 135, 270

The largest number they both have in common is 30, so the largest tile could be 30 cm^2.

5 0
2 years ago
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